Array from vector.

[Hulag]

I have a variable called Numbers of type NumberContainer which is defined as

typedef std::vector<unsigned int> NumberContainer;

and I need to get a pointer to the array. I tried

unsigned int *newNumbers = &Numbers[0]

but that points only to the first value in Numbers. How can I fix that?

[ZuK]

I don't understand your question
if you do

  ++newNumbers;

it will point to the second one.
Kurt

[whiteflags]

I really have to wonder why you are using a vector if you want a fixed size array. You can get random access out of a vector too, you know, in constant time.

If you really wanted to do this, I would allocate an array of the size you need for unsigned ints and then use the copy algorithm to place them (specifically if the array you want starts and ends in the middle of the vector where the other numdbers shouldn't be accessed), but again vectors have everything you need out of arrays and more.

[Hulag]

I don't understand your question
if you do

  ++newNumbers;

it will point to the second one.
Kurt

I don't want access each one, I need to point to the whole array. And no, I can't pass a vector to the function, it's a library that requires an array. If possible I would like to avoid looping through the vector and creating an array from there.

[Hulag]

I really have to wonder why you are using a vector if you want a fixed size array. You can get random access out of a vector too, you know, in constant time.

I use a vector because I like the flexibility it provides, when I create the vector I don't know the size it will take. But then I need to send an array to a function which I don't have the source code of so I thought that there was a way to get a fixed size array from a vector.

[whiteflags]

> it's a library that requires an array.
When you pass a fixed size array to a function, it decays into a pointer anyway. so
unsigned int *newNumbers = &Numbers[0];
is correct.