is this the best way...

IS this the best way to write this piece of code. or is there an easier way.

also could someone just post the small function that would work with it cuz i couldnt get it to work even though it looked fine.

Code:

// Guessing Game

#include <iostream>
#include <ctime>


using namespace std;

int main()
{
int rNumber;  // Random number variable
int Guess;    // Your input variable

cout << "Welcome to Reece's, Guess the number game...\n\n\n\n\n";
// random number
srand(time(NULL));
rNumber = rand() % 15 + 1;

cout <<"Enter your answer: \n";
cin >> Guess;
if (Guess > 15 || Guess < 1)
cout << "ERROR. Enter number above 0 and below 15 please: \n";
cin >> Guess;

if(Guess == rNumber)
cout << "Congrats You Win!\n";
else
cout << "You lose!\n";

cout << "The Number is " << rNumber << endl;

system("PAUSE");
return 0;
}

cheers.

If you wanted too, you could let the user guess the number until he gets it right, by carefully crafting a loop, but you did a good job regardless.

The reason your random number isn't working is because you forgot to #include <cstdlib>, where the srand and rand functions are declared.

thanks mate.

hmm, ill try a loop for it.

would this work

while(Guess != rNumber)
cout << "Wrong, guess again!: \n";
cin >> Guess;

>would this work?

There's only one way to find out!

Hmm ok.. lil problem.

if i type over 15 or below 0, it does what i told it to and replies with error, enter number below 15 and over 0, but when i do it again, it just misses this part out and says nope, wrong answer.
i want it to keep saying enter number below 15 and over 0 every time i type a number over 15 and under 0 lol.

Code:

// Guessing Game

#include <iostream>
#include <ctime>


using namespace std;

int main()
{
int rNumber;  // Random number variable
int Guess;    // Your input variable

cout << "Welcome to Reece's, Guess the number game...\n\n\n\n\n";
// random number
srand(time(NULL));
rNumber = rand() % 15 + 1;

cout <<"Enter your answer: \n";
cin >> Guess;
do{
cout <<"ERROR! Enter a number above 0 but below 15.\n"; break;
} while(Guess > 15 || Guess < 0);

do
{
cout << "Nope, wrong answer... Guess again: \n";
cin >> Guess;
}
while(Guess != rNumber);

cout << "Congrats You Win!\n";

cout << "The Number is " << rNumber << endl;

system("PAUSE");
return 0;
}

can someone please point out what im doing wrong with the first do.. while loop plz.

You have to think again about the logic.
Your first do while loop actually is no loop.
it is allwais entered and it will hit the break statment every time. That means not looping at all.
BTW the two loops have to be nested in some way.
Kurt

I would do it something like this instead.

Code:

   for ( ;; )
   {
      cout <<"Enter your answer: ";
      cin >> Guess;
      if ( Guess == rNumber )
      {
         break;
      }
      if ( Guess > 0 && Guess < 15 )
      {
         cout << "Nope, wrong answer...\n";
      }
      else
      {
         cout <<"ERROR! Enter a number above 0 but below 15.\n";
      }
   }

Cheers bud that done it!

may i just ask, what does for

Code:

(;;)

mean?

seen it loads but dont know what the ;; means, and not sure on FOR too. im gonna look into for in a min.

hugo.

Code:

for (;;)

This is just a way to do an infinite loop.

It has no variables, conditions, or increments.
The reason he made it an infinite loop was because he had an embedded condition with "break" in it.

A normal for loop would be

Code:

for (var = __  ; var < __   ; var++)

-if you take out everything, you still must have the 2 ";" left.


I think another way to do an infinite loop would be

Code:

while (1)
{

}

okie dokie.

cheers bud.