confused with cin.get()

This is a discussion on confused with cin.get() within the C++ Programming forums, part of the General Programming Boards category; hi, Just c the code below: Code: int main() { vector<int> ratings(5); for(int i=0; i<5; i++) { cout<< "enter rating:"; ...

  1. #1
    Registered User
    Join Date
    May 2006
    Posts
    41

    confused with cin.get()

    hi,

    Just c the code below:

    Code:
    int  main()
    {
    
    			vector<int> ratings(5);
    
    			for(int i=0; i<5; i++)
    			{
    				cout<< "enter rating:";
    
    				cin >> ratings[i];
    				
    			}
    
    			
    			for(i=0; i<5; i++)
    			{
    				cin.get();
    				cout<< ratings[i];
    				// cin.get();
    				
    
    			}
    			
    
    
    }
    in the second "for" loop moving "cin. get" after cout<< ratings(i.e deleting the cin.get above cout and adding cin after cout) changes the way output looks.

    In the first case (when cin.get is above cout) the ratings are displayed one after the other on hitting the enter key. In the second case(when cin.get is after cout) if I enter rating say, 1,2,3,4,5 then the output shows 12 and then waits for the enter key.
    Why shud this happen??

    Best Regards,
    Shal

  2. #2
    Registered User
    Join Date
    Apr 2006
    Posts
    25
    Code:
    int  main()
    {
    
    			vector<int> ratings(5);
    
    			for(int i=0; i<5; i++)
    			{
    				cout<< "enter rating:";
    
    				cin >> ratings[i]; // last '\n' is stored on the buffer
    				
    			}
    			
    
    			for(i=0; i<5; i++)
    			{
    				cout<< ratings[i];
                                    /*Start to out put first item, 
                                       then '\n' stored in the buffer is passed to the 
                                       next statement cin.get() */
    				cin.get(); //received the '\n' from buffer at the second looping
    
                                    //the loops works normally from the third item.
    				
    
    			}
    }
    As I explained, the '\n' is stored in buffer result from the last inputting the last item for the vector. Try to ignore the '\n' at the end of the first loop. It will ignore that '\n' when the next cin.get() is called.

    Code:
    int  main()
    {
    
    			vector<int> ratings(5);
    
    			for(int i=0; i<5; i++)
    			{
    				cout<< "enter rating:";
    
    				cin >> ratings[i]; // last '\n' is stored on the buffer
    				
    			}
    			
                            cin.ignore(1000,'\n'); //ignore the last enter
    
    			for(i=0; i<5; i++)
    			{
    				cout<< ratings[i];
    				cin.get();
    
    			}
    Last edited by trongsi; 06-01-2006 at 04:40 PM.

  3. #3
    Registered User
    Join Date
    May 2006
    Posts
    41
    Thanks for ur response!!! I thought there was some \n getting stored in the buffer but i didn't knew how to ignore it

Popular pages Recent additions subscribe to a feed

Similar Threads

  1. cin.get() Troubles
    By yukapuka in forum C++ Programming
    Replies: 19
    Last Post: 06-04-2008, 01:30 PM
  2. cin.get() problem
    By Cilius in forum C++ Programming
    Replies: 20
    Last Post: 07-28-2005, 05:32 PM
  3. Confused about cin.get(); and classes.
    By RaccoonKing in forum C++ Programming
    Replies: 6
    Last Post: 07-17-2005, 11:44 AM
  4. cin.get();
    By swgh in forum C++ Programming
    Replies: 2
    Last Post: 06-29-2005, 07:51 AM
  5. confused.. in selecting my line of deapth
    By jawwadalam in forum A Brief History of Cprogramming.com
    Replies: 4
    Last Post: 05-04-2003, 01:21 PM

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21