int x = new int[3];

is this a way of creating an array of 3 int called x in C++??

(I've seen this somewhere.)

yes it is

but what's the difference between

Code:

int x[3] = {0};

and

Code:

int x = new int[3];

???

> int x = new int[3];
This should be

Code:

int *x = new int[3];

The former creates an array named x, of 3 ints, and zero initialises them. The latter will not even compile.

That syntax isn't quite right. It should be:

Code:

int* x = new int[3];
//...
delete [] x;

This is called dynamic allocation. The benefit is you can allocate whatever sized array you need at runtime. The disadvantage is you have to ensure the delete is called when you no longer need the array.

In C++ an alternative to this could be std::vector

Edit: Wow I'm slow...

to laser light, why won't it compile??

to laser light, why won't it compile??

Read the posts by Salem and JaWiB. You need a pointer to int.

okkkk!!! thanks!!
Sorry for the silly that silly post ;P