Thread: Noob problem - function call

Hi,

I am trying out a recommended book, "C++ Without Fear," and am having a problem with one of the exercises in the book and on the cd.

The exercise states "Write a function named print_out that prints all the whole numbers from 1 to N. Test the function by placing it in a program that passes a number n to it, where this number is entered from the keyboard. The print_out function should have type void; it does not reutrn a vlaue. The function can be called a simple statement: print_out(n);"

Having a bit of difficult doing this on my own, I copied and pasted the exercise from the cd that came with the book.

Code:

// Exercise 04.01.02
// This program prints out numbers from 1 to n,
//  by calling a function.

#include <iostream>
using namespace std;

// Function must be declared before being used.

void print_out(int n);

int main() {
    int n;

    cout << "Enter a number and press ENTER: ";
    cin >> n;

    print_out(n);

    return 0;
}

// Print-out function.
// Prints numbers from 1 to n. 

int print_out(n) {
    int i;

    for (i = 1; i <= n; i++)     // For i = 1 to n,
        cout << i << " ";        //   print i
    return sum;
}

When I try to compile it, it highlights "int print_out(n)" and says, "int print_out redeclared as different kind of symbol."

I don't really know what that means, and am confused as well since I am using the sample provided on the cd, so wonder why it isn't compiling. I am using Dev C++ 4.9.9.2.

Take a close look:

Code:

int print_out(n) {

This should be like the function prototype instead, i.e.

Code:

void print_out(int n) {

But if print_out's return type is void, then:

Code:

return sum;

Must be wrong. In fact, methinks you can safely remove it.

> void print_out(int n);
Here you say it returns void

> int print_out(n)
Here you say it returns int

Pick one as being right, and change the other to match it.