basic code help

Hey, I am new to programming and I was trying to make a basic add program. It is working fine until it asks you if you want to do it again and no matter if I push y or n it does nothing. What am I missing?

Code:

#include <iostream>

using namespace std;

int mult (int a, int b);

int main()       //Trying to make a basic add program. After you add will ask if you want 
{                //to do another problem but isn't. to try and simplize the program erased 
    int a;       //code to make program repeat when you do again and simply put it works 
    int b;       //until i can find out why if statement is not working. 
    char  y, n;
    
    cout<<"Please input the two numbers to be added: ";  
    cin>> a >> b;
    cin.ignore();
    cout<<"  The sum of the two numbers is: "<< mult (a, b) <<"\n";
    cin.get();
    cout<<"Would you like to add again? (y/n): ";
    cin>> y >> n;
    cin.ignore();
    if ( y == y )  {
    cout<<"It works\n";
    }

    
}
int mult (int a, int b)
    {
         return a + b;
    }

Code:

int a = 0, b = 0;
char again = 'y'; // Well the user is only going to be making one choice
                  // so it needs just one variable
while(again != 'n') {    // make sure you compare it to a character
   cout<< "Please enter two digits to add: ";
   cin>> a >>b;
   cout<< "The sum is " <<add(a, b) <<endl;
   cout<< "Got another problem? ";
   cin>> again;
}

Something like that.

when you ask the user if they want to repeat, you only need to input into one char and check to see if that's 'y'. so get rid of the n variable, change cin >> y >> n; to cin >> y; and then your if statement, put single quotes around the second y so that it compares the contents of the y variable to the character y. if (y == 'y'). otherwise it checks to see if y is equal to itself, which will always be true.

>> if ( y == y )

should be

if ( y == 'y' )

citizen's code it a perfect candidate for a do-while loop.