poker full house!!

I want to print out all 3744 possible poker full houses. Right now I am just assigning cards to be numbers. I'll deal with that later. But here is what I have so far and I'm just getting bad data.

Code:

int main()
{
int array[] = {0,0,0,0,0,0,0,0,0,0,0,0,0}; // if there is a pair or
                                                               // 3 of  a kind it will add 1
                                                               // to the appropriate space
int count = 0; //  if count is 2 then there is a full house

  for(int i = 0; i <= 51; i++)
  {
    for(int j = i + 1; j <= 51; j++)
    {
      for(int k = j + 1; k <= 51; k++)
      {
        for(int l = k + 1; l <= 51; l++)
        {
         for(int m = l + 1; m <= 51; m++)
         {
           int i_i = i % 12;   // this is adding up pairs and 3 of a kind
           array[i_i] += 1;
           int j_j = j % 12;
           array[j_j] += 1;
           int k_k = k % 12;
           array[k_k] += 1;
           int l_l = l % 12;
           array[l_l] += 1;
           int m_m = m % 12;
           array[m_m] += 1;

           for(int z = 0; z <= 12; z++)
           {
                if(array[z] == 2) count += 1;
                if(array[z] == 3) count += 1;

              if(count == 2)
              {
               cout <<i<<" "<<j<<" "<<k<<" "<<l<<" "<<m<<endl;
              }
           }
         }
        }
      }
    }
            // this could very easily be wrong but I don't know when and
            // where to reset things
              for(int q = 0; q <= 12; ++q)
                {
                  array[q] = 0;
                }
                count = 0;

  }
  return 0;
}

Anybody out there with any advice??

Conventially, if you want to count from 0 to 99 in C or C++, one writes

Code:

for (int i = 0; i < 100; ++i)

instead of

Code:

for (int i = 0; i <= 99; ++i)

You want to take the numbers mod 13 rather than 12.

This method for detecting a full house is buggy.
Consider
2 Aces
2 Kings
1 Jack

Code:

           for(int z = 0; z <= 12; z++)
           {
                if(array[z] == 2) count += 1;
                if(array[z] == 3) count += 1;

              if(count == 2)
              {
               cout <<i<<" "<<j<<" "<<k<<" "<<l<<" "<<m<<endl;
              }
           }

array[z] == 2 twice, so count becomes 2, but you don't actually have a full house.

You should reset your counters right after you detect a full house. You do 5 increments, then you want to cancel those increments out immediately so that you don't start "accumulating" lots and lots of cards in your counter.

You only need one variable instead of all those i_i, j_j, k_k ext. Just reasign it each time.

Also in order to include all the combinations, you need to also track card suit.