returning 0 doesnt quit out of the function

Code:

    if(testFile.good())
    {
       testFile.close();
       
       int samefile;
       
       cout<<"\nThere is a file at the current save location with the same name...";
       cout<<"\n  <1>Overwrite";
       cout<<"\n  <2>Rename Current File";
       cout<<"\n  <3>Quit";
       cout<<"\n  ->: ";
       cin>>samefile;
       switch(samefile)
       {
                       case 1:
                            File.open(filename.c_str(), ios::out|ios::trunc);
                            File.close();
                            break;
                       case 2:
                            filename.clear();
                            cout<<"\nNew File Name: ";
                            cin>>filename;
                            filename.append(".txt");
                            break;
                       case 3:
                            Quit();
                            break;
                       default:
                               cout<<"\nNot a valid entry!";
                               cout<<"\n  ->: ";
       }
    }
    
    File.open(filename.c_str(), ios::out);      
    if(File.bad())
    {
                cout<<"File could not be created!";
                Quit();
    }
    else
    {
        cout<<"\t\t\t\'"<<filename<<"\' was created!!"<<endl;
        cout<<setfill('-')<<setw(80)<<"-"<<endl;
    }

ok my problem is this...
if the user enter 3 as a choice from the menu... it is suppose to quit...
all my quit function does is return 0;
but... instead... it goes on and creates the file anyway... even if i said return 0;...
is there another way to quit out of the whole function all together?
my objective is to quit if the user wants to quit... but if not create file...


should i do something like this?

Code:

switch(samefile)
       {
                       case 1:
                            File.open(filename.c_str(), ios::out|ios::trunc);
                            File.close();
                            break;
                       case 2:
                            filename.clear();
                            cout<<"\nNew File Name: ";
                            cin>>filename;
                            filename.append(".txt");
                            break;
                       case 3:
                            done=true;
                            break;
                       default:
                               cout<<"\nNot a valid entry!";
                               cout<<"\n  ->: ";
       }
    }
    
     if(done==true)
    {
         Quit();
    }
    File.open(filename.c_str(), ios::out);      
    if(File.bad())
    {
                cout<<"File could not be created!";
                Quit();
    }
    else
    {
        cout<<"\t\t\t\'"<<filename<<"\' was created!!"<<endl;
        cout<<setfill('-')<<setw(80)<<"-"<<endl;
    }

return 0 in the Quit() function will simply return 0 from that function. You may want exit(0);

No. If I remember, all this code was in another function of yours, void MCreateFile(), right?

If your user chooses 3, you want to exit MCreateFile() and return to main().

Just type return; and forget your Quit() function. It doesn't do what you want, if you called it will do absolutely nothing.

There's really no need for the done variable at all. Just call return; for case 3.

A function call in your code is replaced by the function's return value, so if you have this code:

Code:

case 3:
         Quit();
         break;

and Quit() returns 0, then after Quit() exectues, your code is converted to:

Code:

case 3:
         0;
         break;

o ok...thats worked... thank you