Little help?

Code:

 invalid operands of types `const char[12]' and `char[200]' to binary `operator+' 

--- on # line
(filename = "characters\\" + cfullname +".html";)

You need to use strcat for char arrays, or strings:

Code:

(filename = string("characters\\") + cfullname + string(".html");

or

Code:

filename = "characters";
filename += cfullname;
filename += ".html";

Thanks that worked perfectly! i know i think i'm being a bother... and i hate to ask this (hopefully) last question.. as i was continuing on with the program, while waiting for replies i came up with another problem... (( it would seem every 30 lines i run into another problem... ))

I'm back at the dice rolls that were random between 10 and 20... based off the rolls and why i needed them into variables.. depending on the roll i want to add to it.. in a string like:
if roll is a 10 i want to append 10-0 and thats how it would look on the html file and 11 and 12 ... -1 11-1//12-1 ect all the way up to 20-5

so if the rolls are
12
14
11
20
19
16
10

the output would read

12-1
14-2
11-1
20-5
19-5
16-3
10-0

i tried a few pssobilties, but i keep getting the erros cannont covert bewtween char and int.. the char being '-' also those -3, -4 i want to be added like the above, the some of those is '17'... any ideas on this part..

(( i hope this is the last thing wrong with the code...... I'm fairly new to c++ i have worked with it before.. but this is something my friend requested...
i do thank you all for the help.))

I just have a question. Why is it important to format the dice roll this way? Is the second number random like the first? I've not seen a 20-sided die before.

Originally Posted by citizen

I just have a question. Why is it important to format the dice roll this way? Is the second number random like the first? I've not seen a 20-sided die before.

You've obviously not played enough role playing games

its just the way we play... it adds to armor... and no that number is not random its acorrding to the first random number if its 10 -0 is appendded to it..
10-0
11 12 -1
13 14 -2
15 16 -3
17 18 -4
19 20 -5

like that...

well here's what I would do. Not sure if you'd like it, but Prelude taught me how to deal with random numbers. You should probably learn about what I'm doing.

Code:

#include <iostream>
#include <cstdlib>

using namespace std;

// This function helps seed rand() more properly
unsigned time_seed(void)
{
  time_t now = time ( 0 );
  unsigned char *p = (unsigned char *)&now;
  unsigned seed = 0;
  size_t i;

  for ( i = 0; i < sizeof now; i++ )
    seed = seed * ( UCHAR_MAX + 2U ) + p[i];

  return seed;
}

// This function just makes sure that we don't make other rolls 
// occur more common than others
double uniform_distribution (int seed)
{
   return seed * 1. / (RAND_MAX + 1.);
}

int main(void) 
{
   const char *die[10] = 
   { "10-0", "11-1", "12-1", "13-2", "14-2", "15-3", 
     "16-3", "17-4", "18-4", "19-5", "20-5" };

   srand(time_seed());

// Now, the dice roll still works the same, except you are working 
// within the bounds of a string array.
   int r =  uniform_distribution(rand()) * 10;
   cout << die[r];

   cin.get();

   return 0;
}

There's a much simpler way which doesn't involve translating the dice roll to a string - look at this psuedo-program:

Code:

int main ()
{    
    int x = // Some number from 10 to 20;
    x = (x-9)/2;
    cout << x;
}

Right Bench! Wow, that was neat... of course there was nothing wrong with my solution, it just looks complex because that's how I learned random numbers. My only criticism is that you overwrote the value for x. Shouldn't it be?

Code:

int die = 10 + uniform_distribution(rand()) * (10-20); // some random number 10 to 20;
cout << die << "-" << (die-9)/2 << "\n";

Originally Posted by citizen

. My only criticism is that you overwrote the value for x. Shouldn't it be?

Yep, you're right, I should have stored the result in another variable instead of overwriting x. my arithmetic is sometimes better than my programming