Templates: why can't compiler see the definition

I write a simple program
templatex.h

Code:

#ifndef TEMPLATEXH
#define TEMPLATEXH
 
class Templatex
{
public:
	void print();
	template <typename T> 
	T const& getmax(T const &x , T const &y);
};
#endif

templatex.cpp

Code:

#include <iostream>
#include "templatex.h"

using namespace std;

void Templatex::print()
{
	cout << "print";
}
template <typename T>
T const& Templatex::getmax(const T &x, const T &y)
{
	if ( x>y )
		return x;
	else
		return y;
};

templateuse.cpp

Code:

#include <iostream>
#include "templatex.h"
using namespace std;

int main()
{
	Templatex* t=new Templatex();
	t->print();
}

Here in main why can not we call t->getmax();
Why can not compiler see the definition befaore main?

they said that:
"When a function template is used in a way that triggers its instantiation, a compiler will (at some point) need to see that template's definition."

Can someone clarify this subject please .I don't understand.
I am looking for your answers.
Thanks.

People usually either #include the .cpp file, or more often, the implementation of the template class is contained entirely in the header file.

Templates are not compiled until they are used, so the entire template, not just the prototypes, must be in the header file. To separate parallel normal classes, the definitions can be put into a *.cpp file. You would than #include the *.cpp file in the header.

Thanks IfYouSaySo
thanks King Mir
I think i don't understand this because i don't know what compiler do while compiling and the factor of the .h and .cpp files.In my example where does compiler start to compile.We have 3 files :
1-)templatex.h
2-)templatex.cpp (implemantaion of .h file)
3-)templateuse.cpp.(main)
What is its compiling order.I aassume that(i don't know it is right or wrong please correct:

First start templateuse.cpp and in its preprocessors there is an include file that templatex.h.So before main it compile templatex.h and its implemention file templatex.cpp.So we have binary format of our template function.

But this must be wrong.Because some errors occurs.

1-)What are the wrongs in my definition.What is compiling order's of the .cpp files and .h files in c++ projects.

2-)For header files(e.g:templatex.h).How does compiler knows its definition is in the templatex.cpp .What is happening under the hood?Because their names are the same "templatex" or something different?(this question's answer is very important for me).

Thanks again for your answers.

*.h files and anything included in them are not compiled. Neither are *.cpp files with only teplate class definitions (although your compiler may compile an empty *.o in that case).

In your example I would #include "templatex.cpp" at the end of templatex.h, which is then included in templateuse.cpp.

Also, you need to make your entire class into a template, not just getmax() like this:

Code:

	template <typename T> 
class Templatex
{
public:
	void print();
	T const& getmax(T const &x , T const &y);
};

2-)For header files(e.g:templatex.h).How does compiler knows its definition is in the templatex.cpp .What is happening under the hood?Because their names are the same "templatex" or something different?(this question's answer is very important for me).

It knows the definition is in templatex.cpp because that's where it first encounters when reading templateuse.cpp. Remember, a #include statement effectively inserts the included file into the file doing the including. So #including templatex.cpp has the same effect as coping its contents in its place.

Also, templatex can have any valid c++ exetention, including *.h.

http://www.parashift.com/c++-faq-lit...html#faq-35.12

ok friends i understand it now.
Thanks
good works...