Digits reverse

i have write a program digits reverse.......but prob here....how to gets output with negatif number....

e.g
input : -123456
output : -654321

this my program

Code:

#include <iostream>
#include <stdlib.h>

using namespace std;

int main()
{
int a,b,c,d,e,f,sum,find=0;

cout << "Enter an integer digits: ";
cin >> sum;


a = (sum % 10);

b = (sum % 100);
b = b / 10;

c = (sum % 1000);
c = c / 100;

d = (sum % 10000);
d = d / 1000;

e = (sum % 100000);
e = e / 10000;

f = (sum % 1000000);
f = f / 100000;


        if (sum<10)
          {  
            cout << "The Reverse Order is   : " << endl;
            cout << a << endl;
           } 
        else if (sum<100)
         {
            cout << "The Reverse Order is   : ";
            cout << a << b << endl;
          } 
        else if (sum<1000)
          {
            cout << "The Reverse Order is   : ";
            cout << a << b << c << endl;
          }
         else if (sum<10000)   
          {
            cout << "The Reverse Order is   : ";
            cout << a << b << c << d << endl;  
           } 
         else if (sum<100000)
           {        
            cout << "The Reverse Order is   : ";
            cout << a << b << c << d << e <<  endl;  
           }
          else if (sum<1000000)   
          {        
            cout << "The Reverse Order is   : ";
            cout << a << b << c << d << e << f << endl;  
          }
          
          else if ((sum<0) && (sum<10))
          {
            cout << "The Reverse Order is   : ";
            cout <<"-"<< a << endl;
          }
  
       
         
  cout << "\n\n\n\n";       

 system("PAUSE");
 return 0;
 
 }

Code:

/* ...Before the parsing... */

if (sum < 0) {
   sum *= -1;
   isNegetive = true;

/* ... After the parsing ... */

if (isNegetive)
   sum *= -1;
   // Or if you wish...
   // cout << a * -1 << b ...

i have write a program digits reverse

You can do the whole program in only a few lines that will handle any size number if you turn the number into a string type and then reverse the string.

Originally Posted by SlyMaelstrom

Code:

/* ...Before the parsing... */

if (sum < 0) {
   sum *= -1;
   isNegetive = true;

/* ... After the parsing ... */

if (isNegetive)
   sum *= -1;
   // Or if you wish...
   // cout << a * -1 << b ...

input :-123456
output:-6-5-4-3-2-1

7stud....
im a beginner....so i write the program how i understand...
u have any tips??...i appreciate it...thanks

Originally Posted by mufanz

input :-123456
output:-6-5-4-3-2-1

Congratulations, all that means is you implemented it wrong. You're only supposed to multiply the leading digit a by -1.

thanks....program success

Code:

#include <iostream>
#include <string>
#include <sstream> //ostringstream
using namespace std;

int main() 
{
	int num = 1234;

	ostringstream myOutputString; //creates a special kind of variable(see below)

	myOutputString<<num; 
	//myOutputString works just like 'cout'
	//except you're outputting 'num' into a variable
	//instead of to the console window.
	//You can output any type into the variable.


	string myString = myOutputString.str();
	//the str() function returns a string that contains
	//whatever is inside myOuputString
	
	cout<<"This is now a string: "<<myString<<endl;

	//strings have many functions for manipulating them,
	//but you can just use a string's length() function and a for 
	//loop to reverse a string.  A string can be treated just like
	//and array of characters.

	string reversed;

	for(int position = myString.length() - 1; position >= 0; position--)
	{
		reversed = reversed + myString[position];
	}

	cout<<reversed<<endl;

  	
    return 0;
}