Array initializing

hi all,

Code:

---

#include <iostream>
using namespace std;

class A
{
        public:
        int i;
        A(int i):i(i)
        {

                cout<<"A created "<<i<<endl;
        }
        ~A()
        {
                cout<<" A Destroyed "<<i<<endl;
        }
        A()
        {
                cout<<"A() called"<<endl;
        }
};

class B:public A
{
        public:
                B(int j):A(j)
                {
                        cout<<"B created "<<i<<endl;
                }
                B(){ cout <<" B() called"<<endl;}
                ~B()
                {
                        cout<<" B distroyed "<<i<<endl;
                }
          };

int main()
{
        A a(100);
        B b(200);
        A j[] = {A(1),B(2)};
        return 0;
}

---

the output of this would be

A created 100
A created 200
B created 200
A created 1
A created 2
B created 2
B distroyed 2
A Destroyed 2
A Destroyed 2
A Destroyed 1
B distroyed 200
A Destroyed 200
A Destroyed 100

can anyone tell me , how the distructor of B is called, after the initializationg ( A(int) is called, and then when creating B, A(int) is first called, and then B(int), which I understood, what I can't understand is why ~B() is called right after this)

Thank you in advance

Destructors are called first on the last things created. Look at the order of your destructors. It's the exact opposite of your constructor order.

The program's memory is a stack. First In, Last Out.

Code:

---

> A j[] = {A(1),B(2)};

---

This is the same as

Code:

---

A j[] = {A(1),A(B(2))};

---

Note that an object of B is created to initialize an object of A and then promptly thrown away. If you printed something from A's copy constructor you would get the following for the A(B(2)) -part:

...
A created 2
B created 2
A copy created 2
B distroyed 2
A Destroyed 2
A Destroyed 2
...