Thread: save the day, help a newb.

Look at this example:

Code:

#include <iostream>
using namespace std;

int main()
{
	for(int i = 0; i<10; i++)
	{
		cout<<i<<" ";
	}
	
	cout<<endl;
	return 0;
};

Output:

0 1 2 3 4 5 6 7 8 9

The first thing that happens in that for-loop is that the variable i is created and assigned the value 0:

Code:

for(int i = 0; i<10; i++)

That assignment only executes the first time through the for loop.

Next, the conditional is tested to see whether the statements inside the body of the for-loop should be executed:

Code:

for(int i = 0; i<10; i++)

If the conditional evaluates to true, then the statements inside the body of the for-loop are executed:

Code:

for(int i = 0; i<10; i++)
{
	cout<<i<<" ";
}

If the conditional evaluates to false, then the statements inside the for-loop are skipped, and execution continues with the next statement after the for loop:

Code:

for(int i = 0; i<10; i++)
{
		cout<<i<<" ";
}
	
cout<<endl;

The conditional is tested every time through the for-loop.

After the statements inside the for loop execute, the third piece of code in the for-loop header is executed:

Code:

for(int i = 0; i<10; i++)

That says to increment the variable 'i' by one. That executes at the end of every loop.

So, the first time through the loop, i is set equal to 0. Then the conditional is evaluated: since 0 is less than 10, the statements inside the body of the for loop are executed. After all the statements inside the for-loop execute, i is incremented by 1, so i is then equal to 1. Thereafter, execution jumps up to the for-loop header again. The assignment where i is set equal to 0 is skipped(remember that only executes the first time through the loop), so the conditional is evaluated. Since 1 is less than 10, the statements inside the for loop execute again. At the end of the loop, i is incremented by 1 again, so i is then equal to 2. Once again execution jumps up to the for-loop header, and the conditional is evaluated. Since i is equal to 2 and 2 is less than 10, the statements inside the for loop execute again...etc., etc.

See if you can guess the output of this code:

Code:

#include <iostream>
using namespace std;


int main()
{
	for(int i = 5; i<10; i=i+2)
	{
		cout<<i<<" ";
	}

	cout<<endl;

	return 0;
};

i think 7stud's explaination could be used as a tutorial

In reference to 7stud's request concerning the "for" loop:

"i" is the declared variable which is given a value of 5.

5 is less than 10 according to the condition which is evaluated. After the condition is evaluated and found to be true. The third command, "i=i+2" is initiated. 5 is substituted for "i" therefore 5+2 comes out to be 7.

That is incorrect. The output would be different if that were true.

Originally Posted by subteranneous

5 is less than 10 according to the condition which is evaluated. After the condition is evaluated and found to be true. The third command, "i=i+2" is initiated. 5 is substituted for "i" therefore 5+2 comes out to be 7.

It's important to understand when each statement in the for loop is resolved. The first statement (the initialization) is done first, it's done once and only one. Then the condition is checked. If it returns true, then it goes through the looping statement. After it completes that, it goes to the top, does the update statement, then it checks the condition again. It's important to understand that the loop is done BEFORE the condition is updated.

Code:

for( int i = 0;// Variable initialization. This is done first.
     i < 10;   // Condition. This is done second.
     i++ ) {   // Variable Update. This is done last.
     // The Loop. This is done third.
     std::cout << i << '\n';  // The first time through, this will output 0.
     // End of loop.
     }