ignoring '/' when inputed by user

This is a discussion on ignoring '/' when inputed by user within the C++ Programming forums, part of the General Programming Boards category; I'm writing code that involves people putting in dates... They must use month/day format (2 digits each... 02/01)... My output ...

  1. #1
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    ignoring '/' when inputed by user

    I'm writing code that involves people putting in dates... They must use month/day format (2 digits each... 02/01)... My output is suppose to determine what Zodiac sign they fall under.

    I know I'm doing it the long way with if/else if statements, but I don't know another way.

    My problem is that the user MUST according to the assignment enter the '/' between numbers. my program wants to divide... I've tried to used
    Code:
    cin.ignore(/)
    , but that doesn't seem work... I need to be able to grab the first 2 digits and last 2 into a variable. Is
    Code:
    cin.get
    the answer? If so, what do I put in paren to grab those numbers?

  2. #2
    Confused Magos's Avatar
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    One way is to use streams:
    Code:
    int Month;
    int Day;
    char Dummy;
    std::cin >> Month >> Dummy >> Day;
    The / will be read into the dummy variable.
    This method will NOT make any difference on 2 and 02 though. If this is important you could try to read 5 characters, 2 for month, 1 dummy, 2 for day.
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    If you used ignore, it would be cin.ignore(), not cin.ignore(/). You just have to assume that the character that is being ignored is '/'.

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    Quote Originally Posted by Magos
    One way is to use streams:
    Code:
    int Month;
    int Day;
    char Dummy;
    std::cin >> Month >> Dummy >> Day;
    The / will be read into the dummy variable.
    This method will NOT make any difference on 2 and 02 though. If this is important you could try to read 5 characters, 2 for month, 1 dummy, 2 for day.
    Can I limit the space that each takes up like?

    cin>>Month[2]>>Dummy[1]>>Day[2];

    Or would I limit it within int

    int Month[2];
    char Dummy[1];
    int Day[2];

  5. #5
    Confused Magos's Avatar
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    Code:
    char Month[2];
    char Day[2];
    char Dummy;
    
    std::cin >> Month[0] >> Month[1] >> Dummy >> Day[0] >> Day[1];
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    This isn't doing it... I was trying to get it to display... make sure that it's reading what's being inputed and I get wierd character in between the numbers

    Code:
    cin >> Month[0] >> Month[1] >> Dummy >> Day[0] >> Day[1];
    cout<<Month<<" "<<Day;
    I was trying to display the numbers back to myself to verify they went in correctly... i'll try it with some math and see if they work.


    edit: didn't capitalize
    Last edited by liquidcourage1; 03-02-2006 at 07:44 PM.

  7. #7
    Confused Magos's Avatar
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    Month and day is an array of characters, NOT an integer. Trying to print it like you do is dangerous since the compiler thinks it's a string, but it has no terminating NULL character.

    What exactly are you trying to do, if you need the month/day as a whole number I still recomend my initial suggestion.
    MagosX.com

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    Here's the exact program from the assignment:

    Write a complete program that tells zodiac signs. Ask the user for their birth month and day. Let the user that thye MUST enter the information as follows:
    numeric month/numeric date. For example: 4/13

    Given that information, tell the user which zodiac sign they are. Here's a list:

    * Aries - March 21 - April 20
    * Taurus - April 21 - May 21
    * Gemini - May 22 - June 21
    * Cancer - June 22 - July 22
    * Leo - July 23 -August 21
    * Virgo - August 22 - September 23
    * Libra - September 24 - October 23
    * Scorpio - October 24 - November 22
    * Sagittarius - November 23 - December 22
    * Capricorn - December 23 - January 20
    * Aquarius - January 21 - February 19
    * Pisces - February 20- March 20
    I think I need to use logic statements so I can define month/day and where they fall... like if month = x and day is < y then you are a capricorn, etc.

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    Here's what I'm working with now... Lots of <b>if</b> statements to do it though...
    Code:
    //This program will help determine zodiac sign
    #include <iostream>
    using namespace std;
    
    int main()
    {
    	int month,day;
    
    	cout<<"Please enter your Birth month (2 digit form)\n";
    	cout<<"Example:  February = 02\n\n";
    	cin>>month;
    	cout<<"\n\nPlease enter the Day of your birth (2 digit form)\n";
    	cin>>day;
    	if (month==01 && day<=20)
    		cout<<"Capricorn\n\n";
    	if (month==01 && day>20)
    		cout<<"Aquarius\n\n";
    	if (month==02 && day <=19)
    		cout<<"Aquarius\n\n";
    	
    return 0;
    }

  10. #10
    Confused Magos's Avatar
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    I'd use some kind of structure for easy lookup of the sign. Are you allowed to use structs/STL? Perhaps your latest lecture may hint what to use to solve it?
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    Quote Originally Posted by Magos
    I'd use some kind of structure for easy lookup of the sign. Are you allowed to use structs/STL? Perhaps your latest lecture may hint what to use to solve it?
    No lecture hints unfortunately. This is an online class. I have it almost built until I come into the 8th, 9th month. Says:

    illegal digit '8' for base '8'
    Error for 8 and 9... I don't know how to fix that.

  12. #12
    Confused Magos's Avatar
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    The leading 0 (08) means you're typing in base 8 rather than base 10. Remove the 0 and it'll be fine.

    Footnote: Prefix with 0x to use base 16.
    MagosX.com

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    Teach a man to fish and you feed him for a lifetime.

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    nevermind... i deleted the zero's from 08 to 8 and it works.

    Thanks

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    ha... you typed that when I did... lol

    Just so I know, though... why does it only do that with 8 and 9?
    Last edited by liquidcourage1; 03-02-2006 at 08:15 PM.

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    The leading 0 means that the number is base 8 (octal). Only digits 0-7 are valid in octal, like digits 0-9 are valid in decimal and 0 and 1 are valid in binary.

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