Help please!

Ok I'm very frusterated as this code isnt working right.

Code:

#include <iostream>
#include <iomanip>

using namespace std; 	
int main()

{
	int code, d1, d2, d3, d4, d5, d6, sumtst, rscdaycalc, rndvous;
	char rscday ;
	char chrch = 'church';
	char lrgt = 'largeree';
	char fnt = 'fountain';
	
	cout << "Please enter a code to break: " << endl;
	cin >> code;
	
	d1 = code / 10000;
	d5 = code % 10;
	d4 = (code % 100) / 10;
	d3 = (code % 1000) / 100;
	d2 = (code % 10000) / 1000;
	d6 = code / 100000;
	
	if (d6 != 0)
	{
		cout << "False message: Not a five-digit number." << endl;
		return 0;
	}
	else if (d1 == 0)
	{
	
	cout << "False Message: Not a five-digit number." << endl; 
	return 0;
	}
	
	else
	
	{
	
		sumtst = (d1 + d2 + d3 + d4 + d5);
	 
	 	if ((sumtst % 2) != 0)
	 
	 	{
	 	
	 		cout << "False message: Sum is odd." << endl;
	 		return 0;
	 	}
	 	
	 	else
	 	{
	 	
	 		rscdaycalc = ((d1 * d2) - d3);
	 		
	 			if (rscdaycalc == 1)
	 		
	 			 	rscday = 'Monday' ;
	 			
	 			else if (rscdaycalc == 2)
	 				
	 				rscday = 'Tuesday' ;
	 			
	 			else if (rscdaycalc == 3)
	 			
	 				rscday = 'Wedesday';
	 			
	 			else if (rscdaycalc == 4)
	 			
	 				rscday = 'Thursday' ;
	 				
	 			else if (rscdaycalc == 5)
	 			
	 				rscday = 'Friday' ;
	 			
	 			else if (rscdaycalc == 6)
	 			
	 				rscday = 'Saturday' ;
	 				
	 			else if (rscdaycalc == 7)
	 			
	 				rscday = 'Sunday' ;
	 			
	 			else
	 			{
	 				cout << "False message: Invalid rescue day." << endl;
	 				return 0;
	 			}
	 		}
	 			if ( d4 > d5)
	 			{
	 			rndvous = (d5 + 1);
	 			
	 			if (rndvous == 2)
	 				rndvous = fnt ;
	 					 			
	 			else if (rndvous == 7)
	 				
	 				rndvous = lrgt ;
	 				
	 			else if (rndvous == 8)
	 			
	 				rndvous = chrch ;
	 				
	 			else
	 			{
	 				cout << "False message: Invalid rendezvous point." << endl;
	 			return 0;
	 			}	
	 			}
	 			
	 		else if (d4 < d5)
	 		{
	 				rndvous = (d5 - 1);
	 				
	 				if (rndvous == 2)
	 			
	 				rndvous = fnt;
	 			
	 			else if (rndvous == 7)
	 				
	 				rndvous = lrgt ;
	 				
	 			else if (rndvous == 8)
	 			
	 				rndvous = chrch ;
	 				
	 			else
	 			{
	 				cout << "False message: Invalid rendezvous point." << endl;
	 				return 0;
	 			}
	 		}
	 				
	 		else
	 			{
	 				cout << "False message: Invalid rendezvous point." << endl;
	 				return 0;
	 			}	
	 }
	 
cout << "Rescue on " << rscday << " at the " << rndvous << endl;
return 0;

}

For starters the compiler comes up with a bunch of errors regarding the char variables. It wont let me make lrgt = large tree or even have the full word wednesday here

Code:

 
else if (rscdaycalc == 3)
	 rscday = 'Wedesday';

also the final print out if everything else works gives me a print out like " rescue on y at 104"

Any help is much appreciated as I'm so stuck and can't figure it out.

In C++, string literals are enclosed in double quotes. char literals(i.e. the characters you assign to a char type variable) are enclosed in single quotes, and char types can only store one character. In C++, a string type is used to store words or sentences(i.e. things that are made up of more than one character). Here is an example:

Code:

#include <iostream>
#include <string>
using namespace std;

int main()
{
	char myChar = 'a';
	string myString = "hello world";

	cout<<myChar<<endl;
	cout<<myString<<endl;

	return 0;
}

Ok so I changed all my char variables to string types. The compiler comes up with an error talking about implicit conversion. I really have no idea how to fix it. Is there some other way to go about this?

I figured out another way to do it and it worked like a charm.

Thanks for your help!