1. ## Integers reversed.....

How do I reverse numbers or words to be backwords after I input those numbers or words.

Like say I input 5789, how do I make it come back out as 9875?

Any help would be much appreciated, thanks.

2. If it is stored as a string, you can use the reverse algorithm. If it is a number, you have to do some math to get each digit and then create a new number with the digits reversed, or you can convert it to a string, reverse it, and convert it back.

3. there's a simple way if you are strictly dealing with ints. i know
that the methods described already are more robust, but just to
point out that things can be done a little differently, try a loop like
this:

Code:
```while (num/10 != 0 || num%10 != 0)
{
printf ("%d", num%10);
num = num/10;
}```
this reverses the order of the number, but any leading 0's are
ignored. the looping condition allows the handling of 0's within
the number and prevents a loop that either finishes too early or
runs infinitely. limited functionality, but conveniently simple.

4. I got it now, thanks guys.

5. i wrote a function to reverse a string, i used it in my base conversion algorithm, use this if you want:

Code:
```std::string revstr(std::string str) {
char tmp;
int l = str.length(), l2 = l - 1, ong;
for (ong = 0; ong < (l / 2); ong ++) {
tmp = str[ong];
str[ong] = str[l2 - ong];
str[l2 - ong] = tmp;
}
return str;
}```
it's not too efficient but it's good enough for me.

6. Why would you use that to reverse a string when you can use reverse?
Code:
`std::reverse(str.begin(), str.end());`

7. No need to convert to a string first...
Code:
```unsigned int reverseDecimalInteger(unsigned int x)
{
unsigned int result = 0;
do {
result = result * 10 + x % 10;
x /= 10;
} while (x > 0);
return result;
}```

8. well mine was originally from C, and i didn't know that C++ had a reverse funtion...... i just used it when i ported one of my programs from C -> C++.