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I am working on example7-6 from O'Reilly's Practical C++ Programming book. I am finding that I need to enter 'q' twice to quit the program, but the code says to me that I should only need to enter 'q' once. any clues what is going on here? I want the code to be written in a way that I only need to enter 'q' once.

Thank you everybody for your assistance in advance.

-- program output ---

% ./calc3 Result: 0
Enter operator and number: q
q
%

--- snip ----

Code:

#include <iostream>

int   result;      // the result of the calculations
char  oper_char;   // operator the user specified
int   value;       // value specified after the operator

int main()
{

  result = 0; // initialize the result

  // loop forever (or until break reached)
  while (true) {
    std::cout << "Result: " << result << '\n';
    std::cout << "Enter operator and number: ";

    std::cin >> oper_char >> value;

    if ((oper_char == 'q') || (oper_char == 'Q'))
      break;

    if (oper_char == '+') {
      result += value;
    } else if (oper_char == '-') {
      result -= value;
    } else if (oper_char == '*') {
      result *= value;
    } else if (oper_char == '/') {
      if (value == 0) {
        std::cout << "Error:Divide by zero\n";
        std::cout << "   operation ignored\n";
      } else
        result /= value;
    } else {
      std::cout << "Unknown operator " << oper_char << '\n';
    }
  }
  return (0);
}

std::cin >> oper_char >> value;

this line put the first character into oper_char, and the next one into value.

somehting more like this appears to be working.

Code:

    std::cin >> oper_char;

    if ((oper_char == 'q') || (oper_char == 'Q'))
      break;

    std::cin >> value;