Thread: date

  1. #16
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    Hi John_
    I do not have any problem with these previous links, I fixed all the problem with these in the past. They are working perfectly and gives the right result and I check the out put even manually, and I submitted that part.

    the new requirement for the same file is to get the date from the fistr column just once because,if you check the L_05.csv you will find that all the date column are the same for aspecific date.

    When you said you only getting 0 it is making me because In my runnin or debugging I am getting 10 the dd of the date column.

    the L_05.csv I post is part from I big on, because it did not let me post the whole csv or even zip as it has a big file size. may be thats why you may be getting 0 result. I would like to post you the whole L_05.csv but I am not sure how.

    thank you
    Last edited by hi5; 02-02-2006 at 07:37 AM.

  2. #17
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    any idea

    if I am getting only the dd from the dd/mm/yyyy so I think my format is not right for the function.

    any ideas I am absolutly stack with this function

    I do not think SIZE is the problem becuase even if you change the code to SIZE=9 is giving wrong result only 0s.


    If I know how to solve it I would but I am not, that why I came to you guys, any suggestion with it.
    Last edited by hi5; 02-02-2006 at 07:43 AM.

  3. #18
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    Sorry if my questions seem pointless, the reason I am asking them is to try and understand the code better and see if something could be causing a problem. The reason I thought the SIZE was the problem, was because I thought you wanted it to output the other columns.

    Now I know that you only want to output 1 column it makes sense.

    Is there 1447 lines in this file?

  4. #19
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    For a start you could try to make clear what you really want. You say you want to find out a date from the first column of a csv-file. At the same time you declare your function that is supposed to return the date with a return-type of float. So how do you want to encode a date in a float ?. Your code looks like you are reading a lot of lines from the file but at the same time you say all lines contain the same date. You say you want to post a sample csv-file but you post an xls-file. ( i cannot read that. this is not a windows-box ). If the forum doesn't let you post the csv you could just rename it. If its too big, post a part of it.
    You are making it hard to help you.
    Kurt

  5. #20
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    Hi John_
    yes 1447 row and 196 column, in my original csv file I left the first 6 row as they not rquire. from 7 row where you will find the heading of each column, starting from row 8 you will find the 10/10/2004.

    in that file the date of the first column will repeated in all the 1447 rows, so getting one value of the date would be more than enough.

    I really sorry for keep asking, as I feel Iam lost and thank you for all you effort to solve my problem, I am gratefull.

    can anyone suggest a new function or a way to get that date only once.
    Last edited by hi5; 02-02-2006 at 09:12 AM.

  6. #21
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    This way you can get the value of any column in the file as string.
    If you need the date in some other format you have to convert it.
    Code:
    #include <iostream>
    #include <sstream>
    #include <fstream>
    #include <string>
    
    using namespace std;
    
    // string GetdateValue(int column,string line) {
    string GetColumnValue(int column,string line) {  // use meaningful names
         string temp;
         stringstream sstr(line);
         for( int i = 0; i < column; ++i )
            getline(sstr,temp,',');  // read into temp separated by ','
         return temp;                // return last read value
    }
     
    int main() {
        ifstream input_file("Log_05.txt");// is a scv file have many coulmn first column of it is the date
        string line;
        int count;
        string date_str;   // they are all the same
        string time_str;   // for demonstration
         
        if ( input_file.fail ()) { 
             cout << "Error opening file.";
         }
         else  {
             count = 0;
             while( getline(input_file,line) && count <= 1447) {  // while there is no error and linecount < 1448 if you want it like this
                if ( count == 20 ) {         // get date from line 20 
                   date_str = GetColumnValue( 1, line ); // date is col 1
                   time_str = GetColumnValue( 2, line ); // time is col 2
                }
                count++;        // Increment the count, to go to the next line
             }
             cout << "date is '"<< date_str << "' time is '" << time_str << "'" << endl;        
        }
        return 0;
    }

  7. #22
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    I really don't believe this.

    I thought the .xls file he uploaded was the csv file but just renamed because the forum didn't accept that attachment type. It is the reason I asked him to post the file so I could see the format of it.

    It wasn't even the correct file I had, I just renamed it to .csv, no wonder I wasn't getting anywhere.

  8. #23
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    thank you all for all the effort, I would not be able to do it without your help.

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