Thread: HelperZ

I have been owrking on a login script using pointers to store the passwords in a single pointer to access later when you try to log in. Here is my script, I need to know what is wrong with this, it won't let me put these variables into the pointer, why? please tell me how.

#include<iostream.h>

void main()
{
float login, passwd;
float *store;
cout<<"Please enter your login name:";
cin>>login;
cout<<"\nPlease enter your password:";
cin>>passwd;
*store==passwd;
*store==login;
if(login, passwd != &store)
{
cout<<"\nWould you like to register? y/n";
}
}

well then how do i set those 2 variables to thaty pointer? i want it to be stackable too, so when they register, they will be put on the list, and then when they log in it calls the pointer and lets them in

It calls it an overloaded function as a left operand

you aren't "storing something in the pointer'', you are actually 'pointing the pointer at something''

You actually pointing to the "address" in the memory of it, not the actual thing, hence the "&" operator.

Denethor200, why are you using pointers in this? I see no logic to it unless you are planning to use several different functions in this program and you are trying to overcome the problem of limited scope. If you were trying to do this, you would save each of these variables to the heap rather than using pointers.

Just my thoughts...

Erm, how do I do that?

Okay here is my latest code on this project:
#include<iostream.h>

void main()
{
int login, passwd;
int* log = new int;
int* pass = new int;
*log = login;
*pass = passwd;

char answer;
cout<<"Please enter your login name:";
cin>>login;
cout<<"\nPlease enter your password:";
cin>>passwd;
if(login != log)
{
cout<<"\nWould you like to register? y/n";
cin>>answer;
}
}




now, i need to know why it tells me that log is an *int and login is an int. How do I fix this? I tried usiong &log but it old me it was a **int.