Is there any clean way to print out a fixed-length string (no null terminator)? I realize I can copy the fixed length to a string and print out the null terminated one, but that seems execive. I was thinking if there was a way to cout a set amount of chars? Any help would be appreciated!
-1 for NULL terminator. strlen(..) just if it's NULL-terminated anyways. However you are implementing this.Code:char szBuf[] = "Hello World!\n"; std::cout.write(szBuf, sizeof(szBuf) - 1); std::cout.write(szBuf, strlen(szBuf));
will only work for local arrays, not char* pointers, which is how most code uses string arrays.Originally Posted by Tonto
fireonyx, unfortunately you're gonna have to pass the size with the stringCode:void PrintStr(const char* str) { std::cout.write(str, sizeof(str) - 1); } char szBuf[] = "Hello World!\n"; // outputs "Hello World!" std::cout.write(szBuf, sizeof(szBuf) - 1); // outputs "Hel" on a 32bit platform PrintStr(szBuf);
"I saw a sign that said 'Drink Canada Dry', so I started"
-- Brendan Behan
Free Compiler: Visual C++ 2005 Express
If you program in C++, you need Boost. You should also know how to use the Standard Library (STL). Want to make games? After reading this, I don't like WxWidgets anymore.Want to add some scripting to your App?
maybe this isn't what you're looking for, but what about...
Code:int main() { char buf[] = "Hello World!\n"; for (int i = 0; i < 14; i++) { cout << buf[i]; } cin.get(); return 0; }
"What are all you parallelograms doing here?" - Peter Griffin (to Joe and his wheelchair buddies)
thanks all. I have a class that has several public char[] arrays. The method posted by Tonto works fine. Its been forever since I have done c++, and still getting the hang of it again.
