merging arrays using pointers help!!!

This is a discussion on merging arrays using pointers help!!! within the C++ Programming forums, part of the General Programming Boards category; here is the original code it works but it must use pointers so it is not considered correct help? int ...

  1. #1
    Registered User edshaft's Avatar
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    Question merging arrays using pointers help!!!

    here is the original code it works but it must use pointers so it is not considered correct help?
    int array(int a[], int na){
    for(int ia=0, ia<na;ia++){
    cout<<"Enter a number: ";
    cin>>a[ia];}
    return o;}
    int bubblesort(int a[], int na){
    for (int pass=0; pass<na; pass++){
    for(int ia=0;ia<na-1;ia++){
    if(a[ia]>a[ia+1]){
    int j=a[ia];
    a[ia]=a[ia+1];
    a[ia+1]=j;}}}
    return 0;}
    int merger(int a[],int b[],int c[],int na, intnb, int nc){
    int ia,ib,ic;
    ia=ib=ic=0;
    while(ia<&&ib<nb){
    if(a[ia]<b[ib])
    c[ic++]=a[ia++];
    else if(b[ib]<a[ia])
    c[ic++]=b[ib++];
    else{ c[ic++]=a[ia++];
    ib++;}}
    while(ia<na)
    c[ic++]=a[ia++];
    while(ib<nb)
    c[ic++]=b[ib++];
    return 0;}
    int main(){
    const int na=8;
    const int nb=12;
    const int nc=20;
    int a[na];
    int b[nb];
    int c[nc];
    array(a,na);
    cout<<"Here is array a: \n";
    bubblesort(,na);
    for (nt ia=0; ia<na;ia++){
    cout<<a[ia]<<" ";}
    array(b,nb);
    cout<<"Herer is array b: ";
    bubblesort(b,nb);
    for(int ib=0;ib<nb;ib++){
    cout<<b[ib]<< " ";}
    merger(a,b,c,na,nb,nc);
    cout<<"Herer is the final array: \n";
    for (int ic=0;ic<nc;ic++){
    if(c[ic]!=c[ic+1]){
    cout<<c[ic]<<" ";}}
    cout<<endl;
    return 0;}
    and here is what i tried and i am totally lost

    #include "stdafx.h"
    #include<iostream>
    using namespace std;
    void array(int a[], int na){
    for(int ia=0; ia<na;ia++){
    cout<<"Enter a number: ";
    cin>>a[ia];}
    // return 0;
    }
    void bubblesort(int a[],int na){
    for(int pass=0; pass<na;pass++){
    for(int ia=0;ia<na-1;ia++){
    if(a[ia]>a[ia+1]){
    int j=a[ia];
    a[ia]=a[ia+1];
    a[ia+1]=j;}}}

    //return 0;
    }
    void merger(int *a[],int *b[],int *c[],int na,int nb,int nc){
    int ia,ib,ic;
    ia= ib= ic=0;
    while(ia<na&&ib<nb){
    if(*a[ia]<*b[ib])
    *c[ic++]=*a[ia++];
    else if(*b[ib]<*a[ia])
    *c[ic++]=*b[ib++];
    else{
    *c[ic++]=*a[ia++];
    ib++;}}
    while(ia<na)
    *c[ic++]=*a[ia++];
    while(ib<nb)
    *c[ic++]=*b[ib++];

    // return 0;
    }


    int main()
    {
    const int na=8;
    const int nb=12;
    const int nc=20;
    int a[na];
    int b[nb];
    int c[nc];
    cout<<"Enter numbers for array a: \n";
    array(a,na);
    cout<<"Here is array a: \n";
    bubblesort(a,na);
    for(int ia=0; ia<na;ia++){
    cout<<a[ia]<<" ";}
    cout<<"\nEnter numbers for array b: \n";
    array(b,nb);
    cout<<"Here is array b: \n";
    bubblesort(b,nb);
    for(int ib=0; ib<nb;ib++){
    cout<<b[ib]<<" ";}
    int *aptr=a[na];
    int *bptr=b[nb];
    merger(*aptr,*bptr,&c,na,nb,nc);
    cout<<"\nHere is the final merged array: \n";
    for( int ic=0;ic<nc;ic++){
    if(*c[ic]!=*c[ic+1]){
    cout<<*c[ic]<<" ";}}
    cout<<endl;
    return 0;
    }

  2. #2
    Registered User edshaft's Avatar
    Join Date
    Nov 2001
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    45

    Cool

    can anyone help because i still cant get any better than the code i posted

  3. #3
    Registered User
    Join Date
    Aug 2001
    Posts
    47
    I think the reason you're not getting any replies is because nobody can read your code. Try putting it in [ c o d e ] tags (but without the spaces of course) and use proper indentation so that people can read it.

    I assume you're trying to take two sorted arrays and create a third sorted array containing the contents of the first two? Look up "mergesort" on google. That ought to help.

  4. #4
    Registered User edshaft's Avatar
    Join Date
    Nov 2001
    Posts
    45

    Lightbulb

    sorry about that boys but it is all right because i figured it out

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