I know how to get a random number and set the seed. My problem herre is I have an array of 50 numbers and i want to give them all random numbers in a for loop or some simple way where i wouldn't have to write something for each one but I can't make them random enough.
>My problem herre is I have an array of 50 numbers and i want to give them all random numbers in a for loop
Is this what you mean?
Code:int array[50]; for (int i=0; i<50; i++) { //Insert your code to generate a random number here array[i] = number generated above; } //Print them out for (int i=0; i<50; i++) { std::cout << array[i] << std::endl; }
heres another way to do it... i dont know what your using but i use Turbo C so i'd have to include stdlib.h... but i dunno if you do to use the rand() function
does that make sense? lol... its an easier way to set the borders on the random number... i figured it might help >.<Code:int array[50]; int minrand=20; //minimum random number int maxrand=50; //maximum random number for (int i=0; i<50; i++) { array[i] = (rand()%(maxrand+1-minrand))+minrand; }
If the numbers can be duplicated, then a simple loop would work fine. If the numbers should be unique, like randomly shuffling the numbers from 1-50 that are in the array, then the solution is to fill the array in order without using rand(), then use random_shuffle() to shuffle the array. If you cannot use something from <algorithm> to do the work for you, then you can use the same technique as random_shuffle uses to get the effect.
