Someone PLS Help

:( My problem is

i want to change each number in string to character that i had assigned as char something[]="ABCDEFGHIJKLMNOPQRSTUVWXYZ";.
for people who dont understand what i mean, here is an example,

array[0]=44, array[1]=11, array[2]=00, array[3]=13, so this is the fomula tat i want to use :
output for 44 is (44-26)+65 = 83, for character 83 = s, for 11 is 11+65 = 76 is character L, 00 is A because 00+65, and the last is 13 + 65 = 78 which is N.

the final output will be S L A N.

Code:

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int ifEven(string str)
{
    string array[15];
    char something[]="ABCDEFGHIJKLMNOPQRSTUVWXYZ";
        int i=0;
        int k=0;
       
    while(i<str.size()-1)
    {
        array[k]=str.substr(i,2);
                cout<<array[k]<<" ";
                i+=2;
                k+=1;
        }
 

}

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Bit of a vague explanation for me, can you give us a better example

> My problem is
That you've asked basically the same question a dozen times, and haven't paid any attention to any of the replies.

Nearly 100 replies to all your threads so far, surely someone must have stubled onto some kind of an answer. Even if they didn't, there's going to be a clue in there for you to work with.

well, i just want to display a character of string from the number of string...

Duplicate thread.

http://cboard.cprogramming.com/showthread.php?t=73358

...also cross posted on other forums.

Quote:

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Originally Posted by gtr_s15

well, i just want to display a character of string from the number of string...

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Code:

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char string[100];
char character = string[number];

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:mad:

Quote:

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Originally Posted by 7stud

...also cross posted on other forums.

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Yeah...can we get a few locked down so that we're not all replying to different threads?

Code:

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#include <iostream.h>
#include <string.h>

using namespace std;

int main ()
{
        int i, n;                                                    NOTE, that the site breaks the alphabet[] string (repair it)
        char alphabet[]="ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789\?!@#$%^&*(),.-_+=:<>/\\\'\"\t "; //assign A to alphabet[0], B to alphabet[1], etc.
        string input, store;
       
        getline (cin, input); //get input, note that you can also use getline for file input.
       
        int input_length = input.length (); //store string lenth, since it will be modified
       
        for (i = 0; i <= input_length; i++)
        {
                if (input.compare (0, 1, " ") == 0) //perforem a function, when a space is found, note that the last number will not be shown here.
                {
                        n = atoi (store.c_str()); //assign the input number to a int.
                        cout << alphabet[n] ; // display alphabet[number].
                       
                        input.erase (0, 1); // erase the space
                        store.erase (); //erase store so you can use it again.
                }
               
                store.append (input, 0, 1); //store one number at the time.
                input.erase (0, 1); //erase the number that you assignd to the store string.
        }
       
        n = atoi (store.c_str());
        cout << alphabet[n] << endl; //show the last number
}

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So, if I input 07 30 37 37 40 88 22 40 43 37 29 63, I get "Hello World!"