variable "char" problem

This is a discussion on variable "char" problem within the C++ Programming forums, part of the General Programming Boards category; I cant get this to work: Code: #include <iostream> using namespace std; int main() { char var_name; cout<<"Please enter in ...

  1. #1
    C++ Master
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    Oct 2005
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    ProgramLand
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    variable "char" problem

    I cant get this to work:


    Code:
    #include <iostream>
    
    using namespace std;
    
    int main()
    {
      char var_name;
    
      cout<<"Please enter in your name...\n";
      cin>> var_name;
      cin.ignore();
      cout<<"Your name is "<< var_name <<"\n";
      cin.get();
    }
    it compiles without any errors but when i enter in a name it bails. if i sent in one character it'll work correctly. How do i get it so that it could with with multiple characters too?

  2. #2
    Just Lurking Dave_Sinkula's Avatar
    Join Date
    Oct 2002
    Posts
    5,006
    Declare var_name to accept multiple characters.
    Code:
    char var_name[100];
    Next question: how do I get it to accept text with spaces in between? Use getline.

    And this.
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

  3. #3
    Registered User
    Join Date
    Apr 2003
    Posts
    2,662
    A char type can only store one char, so use a "string" type instead, which can store an unlimited number of chars:
    Code:
    #include <string>
    ...
    ...
    string name;
    cin>>name;
    Last edited by 7stud; 12-03-2005 at 11:39 PM.

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