Load value to struct.

This is a discussion on Load value to struct. within the C++ Programming forums, part of the General Programming Boards category; Say I have the following structs: Code: struct stA { int Num; stB Other[100]; }One; struct stB { char list[100]; ...

  1. #1
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    Load value to struct.

    Say I have the following structs:

    Code:
    struct stA
    {
         int Num;
         stB Other[100];
    }One;
    
    struct stB
    {
         char list[100];
         int Num2;
    }Two;
    then how would I go about putting a string value into the second struct type stB in position 0 in the location list?

    This is all I can figure, but when I print it all I get is a whole screem of jiberish:

    Code:
    char C[100] = "asdf";
    
    One.Two[0].list = C[100];
    It just doesnt work.. anyone got an idea? do I have to declare it some how else?? I think there is a way to do it using curly brackets but I couldnt get that to work either.. HELP!

  2. #2
    ^ Read Backwards^
    Join Date
    Sep 2005
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    Earth
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    But struct stB will have to be above/before struct stA.

    Code:
    #include <iostream>
    
    using namespace std;
    
    
    struct stB
    {
         char list[100];
         int Num2;
    }Two;
    
    
    struct stA
    {
         int Num;
         stB Other[100];
    }One;
    
    
    
    
    int main()
    {
    
    	
    
    
    	cin >> One.Other[0].list;
    
    	cout << One.Other[0].list << endl;
    
    
    
    
    
    	return 0;
    
    }

  3. #3
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    11
    Ok, I would image this would be the correct way to put the string into the type stB struct, but I get the following error:

    Code:
    One.Two[0] = {"asdf",1};
    I get the error

    Code:
    : error C2059: syntax error : '{'
    : error C2143: syntax error : missing ';' before '{'
    : error C2143: syntax error : missing ';' before '}'
    EDIT: But I cant move them do to my problem.. is there any way of getting that string in that location?

  4. #4
    ^ Read Backwards^
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    You are getting confused on what it an array and what is not.
    "Two" is a struct of type stB, there is only one "Two", but that "Two" has an array in it called list.
    Two.list[i] is valid;
    There is also only one "One" of struct type atA, but that one "One" has an array of type stB.
    So "One" has an array size 100 of type stB; which in turn has an array of size 100 in it.
    So you now have 100 things, and each can hold 100 things.

    If it was One[2]; you would now have an array of stA, in which each one would have an array of size 100 of stB which in each one of those would have a char array of size 100.


    And that is very confusing and why we use more descriptive names for our variables and never use something like “one” or “two”!!!

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