What does ++ mean?

**ElastoManiac** · 11-30-2005

Originally Posted by Dae

a = ++c; //would be 6

I'd rather write

Code:

a = c++ + 1;

it makes more sense, and looks awesome

**7stud** · 11-30-2005

Originally Posted by Daved

Operator precedence doesn't matter in determining whether the value x is set to is the originally pointed to value or the value pointed to after the increment. It only determines whether the pointer is incremented or the value pointed to is incremented. Since ++ has precedence, the pointer is incremented.

What matters as to what value x gets is whether it is prefix or postfix. In this case it is postfix, so x gets the originally pointed to value, and the pointer is incremeneted afterwards.

You got me.

**gtr_s15** · 11-30-2005

C++ = similar to C = C + 1 which also the same as C+=
hope this is helpful

**ElastoManiac** · 12-01-2005

Originally Posted by gtr_s15

C++ = similar to C = C + 1 which also the same as C+=
hope this is helpful

i have allready spoken that!

**Dae** · 12-01-2005

Originally Posted by Daved

Dae, you shouldn't be using ++ or -- on y in your example anywhere. It's all undefined. It worked in some cases for you because of the way memory is laid out on your current platform.

Try making an array and then point y at the array. Then you can see a better (and more legal) version of what's going on.

Oh, yeah. I was just testing in the context of the OP's code (I couldnt tell if it had an array), and didn't expect it to be very legal or good to do, haha. Alright, I'll try that, thanks. Good explanation about the precedence btw.

Code:

 and just to make this thread even more confusing (*x)++ will incremenet the value pointer to by x rather than x pointer itself.

Thats not very confusing... maybe if you didn't have the brackets it would.

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