Switch?

[Drake]

can u put a switch statement inside a switch using the same numbers for cases?

Example:

switch (menu)
    {
    case 1:
        int difficulty;
        std::cout<<"1.Easy"<<std::endl;
        std::cout<<"2.Normal"<<std::endl;
        std::cout<<"3.Heroic"<<std::endl;
        std::cout<<"4.GODLIKE"<<std::endl;
        std::cout<<"Choose a difficulty level:"<<std::endl;
        std::cin>>difficulty;
                switch(difficulty)
                {
                case 1:
                std::cout<<"You chose Easy"<<std::endl;
                break;
                
                case 2:
                std::cout<<"You chose Normal"<<std::endl;
                break;
                
                case 3:
                std::cout<<"You chose Heroic"<<std::endl;
                break;
                
                case 4:
                std::cout<<"You chose GODLIKE"<<std::endl;
                break;
                
                default:
               	std::cout<< "You made an illegal choice.\n"<<std::endl;
               	break;
                }

[Quantum1024]

yes but don't forget the break statement following you're second switch statement at the end of case 1.

[Raigne]

Drake why do you use the std::cout command instead of just doing this...?

#include <iostream>

using std::cout;
using std::cin;

int main()
{
//Program code
//the using std::cout; allow you to use cout without having to put the std:: in front of it everytime.

just a suggestion

[sean]

An even more succinct solution is to just put

using namespace std;

right there, but it's almost always merely a matter of personal style. Drake's method is more common than you'd think.

[dwks]

What you can't do is have duplicate cases:

switch(x) {
case 0:
case 0:
}