Program difficulties

This is a discussion on Program difficulties within the C++ Programming forums, part of the General Programming Boards category; I've provided the whole program so anyone can tell what I'm trying to accomplish. In my last two sub-functions how ...

  1. #1
    Registered User Birdhaus's Avatar
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    Question Program difficulties

    I've provided the whole program so anyone can tell what I'm trying to accomplish. In my last two sub-functions how am I going to keep the loop going after it finds a name (if there is more than one occurance of that name) I don;t want the loop t stop after finding the name just once. I want it to display all occurances of that name.

    Code:
    #include <iostream>
    #include <iomanip>
    #include <math.h>
    #include <ctype.h>
    #include <string.h>
    #include <fstream>
    
    using namespace std;
    
    
    
    /***************************************************************
    Struct: person
    
    ***************************************************************/ 
    struct person
    {
    
    	char personName[30];
    	
    	int amLevel;
    	
    	int noonLevel;
    	
    	int pmLevel;
    
    };
    
    void showAll(person [], char *[], int);
    
    void showName(person[], char *[], int, int);
    
    void showNameLevel(person[], char *[], int, int);
    
    
    
    
    int main(int argc, char *argv[])
    {
       
        ifstream inFile;
    	
    	person patient[25];
    	
    	int i;
    	
    	inFile.open("c:\\Z089933sugar.dat",ios::in|ios::binary);
    
    	if(inFile.fail())
    	{
    	
    		cout<< "Error! Make sure file exists.";
    		
    		exit(1);
    	
    	}
    	
    	inFile.read((char*)&patient[i],sizeof(person));
    	
    	
        while(inFile && i <= 24)
    	{
    		i++;
    		inFile.read((char*)&patient[i],sizeof(person));
    	}
    	
        inFile.close();
    
    	switch(argc)
    	{
    		case 1:
    		    
    			showAll(patient, argv, i);
    			
    			break;
    			
    		case 2:
    		
    			showName(patient, argv, i, argc);
    			
    			break;
    			
    		case 3:
    		
    			showNameLevel(patient, argv, i, argc);
    			
    			break;
    			
    		default:
    		
    			cout<< "Too many arguments!";
    	}
    	
    	return 0;
    
    }
    
    /*********************************************
    Function: showAll
    Use:
    Arguments:
    Returns:
    *********************************************/
    
    void showAll(person patient[], char * argv[], int max)
    {
        int i;
    	
    	for (i = 0; i < max; i++)
    	  {	
            cout << "\nPatient:" << patient[i].personName;
            cout << "\n am level:" << patient[i].amLevel;
            cout << "\n pm level:" << patient[i].pmLevel;
            cout << "\n noon level:" << patient[i].noonLevel;
          }
        return;
    }
    
    /*********************************************
    Function: showName
    Use:
    Arguments:
    Returns:
    *********************************************/
    
    void showName(person patient[], char * argv[], int max, int argc)
    {
         int i;
         int found;
         
         for(i = 0; i < max; i++)
           {
               found = strcmp(argv[1], patient[i].personName);
               
               if(found == 0)
                 {
                        
         
    
    
    }
    
    /*********************************************
    Function: showNameLevel
    Use:
    Arguments:
    Returns:
    *********************************************/
    
    void showNameLevel(person persons[], char * argv[], int max, int argc)
    {
    
    
    
    }
    Any help would be appreciated.

  2. #2
    Registered User
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    You don't have to do anything, the loop will keep going until it hits max or until you break out of it. So just don't break out of the loop and you'll be fine.

  3. #3
    Registered User Birdhaus's Avatar
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    Sorry, I ment in the function "void showName"
    I was told to use the if statement. So how should it work??
    Once I know how to do that then I'll know how to do the showNameLevel function as well

  4. #4
    Registered User
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    I was talking about that function as well. You have a for loop. You want the for loop to continue even if you find the name. Unless you specifically break out of the for loop, it will continue automatically. The if statement should be where you output the data you found when the name matched, or whatever showName is supposed to do.

  5. #5
    Devil's Advocate SlyMaelstrom's Avatar
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    Code:
     // You can knock out the found variable.
    
    if(strcmp(argv[1], patient[i].personName) == 0)   // Meaning you found a match
         cout << "Found match: " << patient[i].personName << '.' << endl;
    
     // and that's it. It'll loop until you real the entire array and continue to output the matches.
    Also, since you've already determinted that argc is 2 by the time you call the function, there is really no reason to pass it to the function in this case.
    Sent from my iPadŽ

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