Having A problem...probably right under my nose

So I dont know why this will not work...everything looks fine.....Ive been writing code for 4hrs this morning so its probably the smallest thing Im missing and ho[ing someone can spot it out for me....thanks in advance....my eyes are bugging!

Code:

#include<stdio.h>

main()
{
	int n;
	printf("Please enter a single digit for a car.\n");
	printf("(within the range of 1 to 3):\n");


	switch(n) {
	case '1':
		printf("Car 1 is a Ford\n");
		break;


		case'2':
			printf("Car 2 is a Chev\n");
			break;

			
			case'3':
				printf("Car 3 is a Foreign\n");
				break;


				default:
					break;

	}

					return 0; //Return to the IDE
	}

What Im trying to do is get is to ask me to input 1, 2 or 3 and it will display Ford, Chev, or Foreign. Its ........ing me off that I cannot find the problem. I get error saying 'n' in not initialized, when it is.

You don't read in anything.
try

Code:

scanf("%d", &n);

That's probably not an error, but a warning. It's telling you that you didn't set a value for n before you used it. Looking at your code, you have no code for reading the input in from the user.

Since you are using C code, you should probably post these questions in the C forum, but the simple answer would be to read in a value for n before the switch.

If you use Quantum1024's suggestion it won't quite work because that code reads in an integer, so n will have 1, 2 or 3. The case statements in the switch are looking at characters: '1', '2', and '3', so they will never match ('1' does not equal 1). To fix it, either change scanf to read in a char, or change your case statements to use integers instead of characters by removing the single quotes.

Thanks guys. Sorry for posting here, Ill post in the C forum.

^^^Daved Nice catch.