I have the following line of code
It produces the following warning messageCode:x=fabsf(x)-f3*0.5*powf(0.5,n);
x, f3, and n are all declared as numbers of the type float.Code:warning C4244: '=' : conversion from 'double' to 'float', possible loss of data
Why do I get this error message, and how can I fix my code so I do not get it in the future?
Perhaps all the code would help.
0.5 is of type double. The float version is 0.5f, this goes for all literals
In general, you should use double unless you have a specific reason to use float for your floating point numbers (float is to double as short is to int). That is why a floating point literal is considered to be a double unless you specifically indicate it should be a float with the f.
