helpp

in

Code:

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ofstream a_file("data.1")

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how can i make the name of the archive be a variable

Take off the quotes.

I don't know how data.1 is a variable name, as '1' is not an acceptable variable declaration, nor is anything with a '.' in it.

A variable is something that holds data.
Put what you want into the variable.

Code:

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#include <iostream>       
#include <fstream>


using namespace std;

int main()
{

        ofstream out;

        char file_name[16];
        cout << "Enter the name of the file (including ext, IE test.txt: ";
        cin >> file_name;

        out.open(file_name);

        out << "See, like this.";

        out.close();

        return 0;

}

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