Just trying to cout an empty set

Can someone explain to me how to cout an empty set from this code? I know that the second idx should reference the array but don't know how to do it.

main.cpp

Code:

int main()
{
	IntegerSet a;

	cout << "Empty Set" << endl;
	a.printSet();
	getch();
}

IntegerSet.cpp

Code:

void IntegerSet::printSet()
{
	for( int idx = 1; idx <= arraySize; ++idx )
		cout << idx << ")" << setw( 3 ) << idx << endl;
}

IntegerSet.h

Code:

#ifndef INTEGERSET_H
#define INTEGERSET_H

const int arraySize = 100;

class IntegerSet 
{
public:
void printSet();

private:
	int array;

};

#endif

I do not see an array anywhere in the code you posted?
But if you did have an array, you would 'cout << array_name[idx]' in your for loop (is one method).

Originally Posted by Enahs

I do not see an array anywhere in the code you posted?
But if you did have an array, you would 'cout << array_name[idx]' in your for loop (is one method).

and make sure it's zero counted i.e. change your code

Code:

for( int idx = 1; idx <= arraySize; ++idx )

to

Code:

for( int idx = 0; idx < arraySize; ++idx )