Just trying to cout an empty set

This is a discussion on Just trying to cout an empty set within the C++ Programming forums, part of the General Programming Boards category; Can someone explain to me how to cout an empty set from this code? I know that the second idx ...

  1. #1
    Registered User
    Join Date
    Feb 2005
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    Just trying to cout an empty set

    Can someone explain to me how to cout an empty set from this code? I know that the second idx should reference the array but don't know how to do it.

    main.cpp
    Code:
    int main()
    {
    	IntegerSet a;
    
    	cout << "Empty Set" << endl;
    	a.printSet();
    	getch();
    }

    IntegerSet.cpp
    Code:
    void IntegerSet::printSet()
    {
    	for( int idx = 1; idx <= arraySize; ++idx )
    		cout << idx << ")" << setw( 3 ) << idx << endl;
    }
    IntegerSet.h
    Code:
    #ifndef INTEGERSET_H
    #define INTEGERSET_H
    
    const int arraySize = 100;
    
    class IntegerSet 
    {
    public:
    void printSet();
    
    private:
    	int array;
    
    };
    
    #endif

  2. #2
    ^ Read Backwards^
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    I do not see an array anywhere in the code you posted?
    But if you did have an array, you would 'cout << array_name[idx]' in your for loop (is one method).

  3. #3
    semi-colon generator ChaosEngine's Avatar
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    Chch, NZ
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    Quote Originally Posted by Enahs
    I do not see an array anywhere in the code you posted?
    But if you did have an array, you would 'cout << array_name[idx]' in your for loop (is one method).
    and make sure it's zero counted i.e. change your code
    Code:
    for( int idx = 1; idx <= arraySize; ++idx )
    to
    Code:
    for( int idx = 0; idx < arraySize; ++idx )
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