Help with Complex Quadratic Problem

This is a discussion on Help with Complex Quadratic Problem within the C++ Programming forums, part of the General Programming Boards category; I've been trying to get this to compile, but it isn't cooperating. Does anyone know what the problem is? else ...

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    Help with Complex Quadratic Problem

    I've been trying to get this to compile, but it isn't cooperating. Does anyone know what the problem is?

    else (discriminant < 0 ) {

    square_root = sqrtf(-discriminant);
    x1 = -b / (2 *a);
    x1_i = square_root / (2 * a);
    x2 = x1;
    x2_i = x1_i;
    printf("There are two complex roots.\n");
    printf("x1 = %f = %f i and x2 = %f - %f i\n", x1, x2, x1_i, x2_i);

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    C++ Developer XSquared's Avatar
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    else if, instead of else.
    Naturally I didn't feel inspired enough to read all the links for you, since I already slaved away for long hours under a blistering sun pressing the search button after typing four whole words! - Quzah

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    Gah. Thanks so much man. Well now I feel like a spoony bard...

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