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Need Help, cannot get char to display A+,F-, etc.

This is a discussion on Need Help, cannot get char to display A+,F-, etc. within the C++ Programming forums, part of the General Programming Boards category; I can get 'A' to display as a char, but not 'A-', what do I have to do to correct ...

  1. #1
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    Need Help, cannot get char to display A+,F-, etc.

    I can get 'A' to display as a char, but not 'A-', what do I have to do to correct this problem. Thank YOu.

    Code:
    #include <iostream>
    using namespace std;
    
    int main()
    {
    	int	exam1, exam2, exam3,
    		homework1, homework2, homework3, homework4, homework5, homework6,
    		quiz1, quiz2, quiz3,
    		ExamScore,
    		HomeworkScore,
    		QuizScore,
    		FinalScore;
    	 char grade;
    
    	cout << "What is your grade on Exam 1?\n";
    	cin >> exam1;
    	cout << "What is your grade on Exam 2?\n";
    	cin >> exam2;
    	cout << "What is your grade on Exam 3\n";
    	cin >> exam3;
    
    	cout << "What is your grade on Homework 1?\n";
    	cin >> homework1;
    	cout << "What is your grade on Homework 2?\n";
    	cin >> homework2;
    	cout << "What is your grade on Homework 3?\n";
    	cin >> homework3;
    	cout << "What is your grade on Homework 4?\n";
    	cin >> homework4;
    	cout << "What is your grade on Homework 5?\n";
    	cin >> homework5;
    	cout << "What is your grade on Homework 6?\n";
    	cin >> homework6;
    	
    	cout << "What is your grade on Quiz 1?\n";
    	cin >> quiz1;
    	cout << "What is your grade on Quiz 2?\n";
    	cin >> quiz2;
    	cout << "What is your grade on Quiz 3?\n";
    	cin >> quiz3;
    
    	ExamScore = ((exam1 + exam2 + exam3) / 3) * .6;
    	HomeworkScore =((homework1 + homework2 + homework3 + homework4 + homework5 + homework6) / 6) * .3;
    	QuizScore = ((quiz1+quiz2+quiz3)/3)*0.1;
    	FinalScore= ExamScore + HomeworkScore + QuizScore;
    
    
    	if (FinalScore < 60)
    		grade = 'F';
    	else if (FinalScore >=60)
    		grade = 'D-';
    	else if (FinalScore >=62)
    		grade = 'D';
    	else if (FinalScore >=67)
    		grade = 'D+';
    	else if (FinalScore >=70)
    		grade = 'C-';
    	else if (FinalScore >=72)
    		grade = 'C';
    	else if (FinalScore >=77)
    		grade = 'C+';
    	else if (FinalScore >=80)
    		grade = 'B-';
    	else if (FinalScore >=82)
    		grade = 'B';
    	else if (FinalScore >=87)
    		grade = 'B+';
    	else if (FinalScore >=90)
    		grade = 'A-';
    	else if (FinalScore >=92)
    		grade = 'A';
    	else if (FinalScore >97)
    		grade = 'A+';
    
    	cout<< "Your final score is "<<FinalScore<<endl;
    	cout<< "Your letter grade is " <<grade<<endl;
    
    	return 0;
    }

  2. #2
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    "A+" and "A-" is NOT one character, but a string. you need to enclose it in double quotes. That means variable grade needs to be a char*, not char because it can take on more than one character at a time.

  3. #3
    Reverse Engineer maxorator's Avatar
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    or char grade[2];

  4. #4
    ^ Read Backwards^
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    D's are 60-69 where you are at? Around here a D is 65-69!...Not that I have ever gotten a D...errr

  5. #5
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    Quote Originally Posted by maxorator
    or char grade[2];
    you forgot the null-terminator!
    char grade[3];

  6. #6
    and the hat of wrongness Salem's Avatar
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    It's C++
    Use
    std::string grade;

    Then
    grade = "A+";

    etc
    iMalc likes this.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

  7. #7
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    Thanks Ancient Dragon. It works on my work.

  8. #8
    and the hat of wrongness Salem's Avatar
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    Forum rule #3
    You should have just clicked the "like" button, rather than digging up a 6 year old thread.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.
    I support http://www.ukip.org/ as the first necessary step to a free Europe.

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