Local Function definitions are illegal.....

**Zerohero11** · 09-07-2005

Hello everyone this is my first post.I was trying to make tihs program using function and everything seemed to be going great....until I compiled. This is just a project I want to work on myself. It's going to be more than what it is now. If anyone can show me what I'm doing wrong please? Thanks. BTW, I'm still a "noob" programmer so cut me a lil slack

**curlious** · 09-07-2005

I think you need to declare the prototypes above main.

**JaWiB** · 09-07-2005

Looks like you're missing the closing brace at the end of main

**Zerohero11** · 09-07-2005

I get this error when I add the brace at the end.

warning C4715: 'main' : not all control paths return a value

**Dave_Sinkula** · 09-07-2005

...using and indenter, this is what you have:

Code:

// Pythagorean Theorem //
// Brandon B //
// 09/04/05//
// This Program was designed to solve problems using the Pythagorean Theorem//


#include <iostream>
using namespace std;

#include <math.h>

int trigequation( int,int);
int subracttrig(int,int);

int main ()
{

   int x;

   cout<< " Solve for which leg?" << endl;
   cout <<" 1 for C" << endl;
   cout <<" 2 for A & B " << endl;

   cin >> x;

   if ( x == 1 )
   {
      int A, B, c,b2;


      cout<< "Enter side A" << endl;
      cin >> A;
      cout <<" Enter side B"<< endl;
      cin >>c;


      B = trigequation (A,c);

      b2 = sqrt(B);

      cout << " size of the leg you entered is" <<""<< b2;


      cout << c <<""<< "is the angle for side C" << endl;
      system("pause");
      return 0;

   }
   else if ( x == 2 )
   {
      int ax,be,c,d;
      cout << "Enter number of side" << endl;
      cin >> ax;
      cout << " Enter number of Hypotenus" << endl;
      cin >>be;

      c = subracttrig(ax,be);

      d = sqrt(c);

      cout <<" The answer for the side you solved is" <<d << endl;

      system("pause");
      return 0;


   }

   int trigequation(int A, int c)
   {
      return(pow( A,2) + pow( c,2));
   }

   int subtracttrig(int ax, int be)
   {
      return(pow(be,2) - pow(ax,2));
   }

**Zerohero11** · 09-07-2005

I recieved this error when doing what you recomended.

error C2601: 'trigequation' : local function definitions are illegal
C:\Program Files\Microsoft Visual Studio\MyProjects\Trig Calc\Pythagorean.cpp(75) : error C2601: 'subtracttrig' : local function definitions are illegal
C:\Program Files\Microsoft Visual Studio\MyProjects\Trig Calc\Pythagorean.cpp(90) : fatal error C1004: unexpected end of file found
Error executing cl.exe.

**Zerohero11** · 09-07-2005

and when I add the brace it gives me this error.

'main' : not all control paths return a value

**Dave_Sinkula** · 09-07-2005

I recommended nothing -- I showed you what you posted.

Originally Posted by Dave_Sinkula

this is what you have

Your answer had already been provided.

[edit]Also, subtracttrig is not the same as subracttrig.

**Zerohero11** · 09-07-2005

Originally Posted by Dave_Sinkula

I recommended nothing -- I showed you what you posted.Your answer had already been provided.

I'm guessing about the prototyping right?

**Dave_Sinkula** · 09-07-2005

No, close the else clause. Or yes -- make the declaration, invocation, and definition all match.

**Zerohero11** · 09-07-2005

Thanks alot guys I got it to work. I thought it was a major problem when it was just a few small minor errors.

**Zerohero11** · 09-07-2005

The correct program:

Code:

#include <iostream>
using namespace std;

#include <math.h>

int trigequation( int,int);
int subtracttrig(int,int);
    

int main ()
{

   int x;
   cout << "Welcome to Pythagorean solver " << endl;	
   cout<< " Solve for which leg?" << endl;
   cout <<" 1 for C" << endl;
   cout <<" 2 for A & B " << endl;

   cin >> x;

   if ( x == 1 )
   {
      int A, B, c,b2;


      cout<< "Enter side A" << endl;
      cin >> A;
      cout <<" Enter side B"<< endl;
      cin >>c;


      B = trigequation (A,c);

      b2 = sqrt(B);

    
      cout << b2 <<":"<< "is the angle for side C" << endl;
      system("pause");

      return 0;

   }
   else if ( x == 2 )
   {
      int ax,be,c,d;
      cout << "Enter number of side" << endl;
      cin >> ax;
      cout << " Enter number of Hypotenus" << endl;
      cin >>be;

      c = subtracttrig(ax,be);
	  

      d = sqrt(c);

      cout <<" The answer for the side you solved is:"<<"=" <<d << endl;

      system("pause");
      return 0;


   }

   return 0;
}
   
int trigequation(int A, int c)
   {
      return(pow( A,2) + pow( c,2));
   }

   int subtracttrig(int ax, int be)
   {
      return(pow(be,2) - pow(ax,2));
   }

**curlious** · 09-07-2005

I apoligize about the prototyping comment. I was not looking closely.

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