cin.getline anamoly??

This is a discussion on cin.getline anamoly?? within the C++ Programming forums, part of the General Programming Boards category; I don't get it. so i have a program. the follow function is executed when I make a selection on ...

  1. #1
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    cin.getline anamoly??

    I don't get it. so i have a program. the follow function is executed when I make a selection on the main menu of the program.

    Only when i write "cin.getline (ch2,21);"twice this function works right. It prompts you,then you write your string, and it prints the correct values.

    if i type "cin.getline (ch2,21);" once, it will just skip the line that asks you to type in a string.. what's the deal??



    Code:
    void StringType(void)
    {
    	char ch2[21];
    	char conti6;
    	int *strp;
    	int straddr;
    
    	cout << endl;
    	cout << endl;
    	cout << "Enter a string (20 char max):";
    	//cin >> ch2;
    	
    	cin.getline (ch2,21);
    	cin.getline (ch2,21);
    
    	strp = (int*)(&ch2);
    	straddr = int(strp);
    	
    	cout << endl;
    	cout << endl;
    	cout << "Address:0x";
    
    	straddr = int(strp);		//bit shifting for output formatting
    	straddr &= 0xFF000000;
    	straddr = straddr >> 24;
    	straddr &= 0x000000FF;
    	if(straddr < 16) cout << "0";
    	cout << hex << straddr << " ";
    
    	straddr = int(strp);
    	straddr &= 0x00FF0000;
    	straddr = straddr >> 16;
    	if(straddr < 16) cout << "0";
    	cout << hex << straddr << " ";
    
    	straddr = int(strp);
    	straddr &= 0x0000FF00;
    	straddr = straddr >> 8;
    	if(straddr < 16) cout << "0";
    	cout << hex << straddr << " ";
    
    	straddr = int(strp);
    	straddr &= 0x000000FF;
    	if(straddr < 16) cout << "0";
    	cout << hex << straddr << " ";   // bit shifting end.
    
    	cout << endl;
    	cout << "ASCII code:0x ";
    
    	for(int j = 0; j != 21; j++)
    	{
    		if(int(ch2[j] == 0))
    		{
    		cout << "00";
    		break;
    		}
    		cout << int(ch2[j]) << " ";
    
    	}
    
    
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    
    	while(1)
    	{
    		cout << "press 'c' and then enter to continue:";
    		cin >> conti6;
    		cout << endl;
    		if(conti6 == 'c' || conti6 == 'C') break;
    	}
    
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    	cout << endl;
    
    }

  2. #2
    Compile Errors = Schwa?!
    Join Date
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    Location
    Ohio
    Posts
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    Could you post the code of the function that is calling it?

    I'm thinking the problem is with the function that calls this function. wherever you have:

    Code:
               int Input;
    
               cin>> Input;
               
    switch (Input) {
                      case 1:
                                 //code
                      case 2:
                                 //code
                      default:
                                //code
                      }
    
    //You need cin.ignore(); after cin>> Input;
    I'm pretty new to C++ so I could be wrong.

  3. #3
    ... arjunajay's Avatar
    Join Date
    May 2005
    Posts
    203
    You get this when you mix cin>> and cin.getline();
    Try a board search. This same question comes atleast twice week.

  4. #4
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    lol. very true. and i've asked one of those questions too.

    if you're using msvc++, get the free sp6 download from ms. and then apply the tiny change if it already hasn't been implemented in sp6.

  5. #5
    Registered User
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    i've tried just using cin >> ... but it does work either.. anyway.. thanks i'll do a search

  6. #6
    Registered User
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    thanks, saw the answer in another post

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