turning real (number) variables into stirngs

I am pretty sure it is possible, but I am not sure how to turn a real variable into a string variable (using string.h).

I was given some of these links looking for the same thing:

http://rafb.net/efnet_cpp/faq/conversions/int2string/
http://www.parashift.com/c++-faq-lit....html#faq-39.1
http://www.boost.org/libs/conversion/lexical_cast.htm

And I was given some code that works similrly to atoi by another member:

Code:

---

void append_int(std::string & s, unsigned int n)
{
    unsigned int tmp = 0;

    while (n) {
      tmp *= 10;
      tmp += n % 10;
      n /= 10;
    }

    while (tmp) {
        s.push_back('0' + tmp % 10);
        tmp /= 10;
    }
}

---

I wrote this assuming by <string.h> you meant <string> and std::string's. If you merely wanted char* strings, than you can use atoi() in <cstdio>

Alright and yes I ment string not string.h. That first link you gave me worked perfectly!

Thanks for passing along the help!

You could use stringstreams. Do a board search if you want more. They've been discussed several times recently. Just, use them as a normal stream when dealing with floating point numbers.

And, atoi( ) goes the wrong way. ;)

Damnit! itoa() ;)

There is only a minor problem with that one:

Quote:

---

Portability.
Not defined in ANSI-C. Supported by some compilers.

---

Best sticking with:
1. stringstream
2. sprintf
3. your own "home-brew" function

With heavy preference for the first.

Cheers

This is in the faq...

Code:

---

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

int main()
{
        int x = 10;
        string s;
        stringstream ss;
        ss << x;
        s = ss.str();
        cout << s << endl;
        cin.get();
        return 0;
}

---

I usualy do it like this:

(string)(char*)variable

i dont think you have ever really used that...
and had it work, at least if this is what your meaning
by your post

Code:

---

#include <iostream>
#include <string>

using namespace std;

int main()
{
        int length = 10;
        string mystring = (string)(char*)length;
        cout << mystring << endl;
        cin.get();
        return 0;
}

---

cause it doesnt work.

Quote:

---

Originally Posted by ILoveVectors

Code:

---

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

int main()
{
        int x = 10;
        string s;
        stringstream ss;
        ss << x;
        s = ss.str();
        cout << s << endl;
        cin.get();
        return 0;
}

---

---

That is exactly what I am using.

Quote:

---

Originally Posted by Tonto

Code:

---

void append_int(std::string & s, unsigned int n)
{
    unsigned int tmp = 0;

    while (n) {
      tmp *= 10;
      tmp += n % 10;
      n /= 10;
    }

    while (tmp) {
        s.push_back('0' + tmp % 10);
        tmp /= 10;
    }
}

---

---

Just make sure you don't use this function for any value of n that is ten digits long and ends in 4, 5, 6, 7, 8, or 9. [Some values that end in 4 work -- namely those with tens digit 1 or 0. Most ten-digit numbers that end in "24" also work -- but if the hundreds digit is 9, they might not. (If the reversed form of the number is 4294967296 or higher, the function breaks.)] Assuming that an int is 32 bits long.

I'd go with using a char array as a stack instead of another int, next time around. So just use stringstreams :-)

Check out wsprintf()

wsprintf is for use with wchar_t, not char. sprintf would generally be the appropriate function.