Converting Text to Binary (And Back)

You can use the bitset member to_ulong to make the conversion.

Code:

#include <iostream>
#include <string>
#include <vector>
#include <bitset>

using namespace std;

int main()
{
   string pizza("CHEESE");
   vector < bitset<8> > b;

   for (int i=0; i<pizza.length(); i++)
      b.push_back(pizza[i]);
        
   for (int i=0; i<b.size(); i++)
      cout << b[i] << endl;

   string pizza_name;
   for (int i=0; i<b.size(); i++)
   {
      char c = b[i].to_ulong();
      //cout << (int) c << endl;
      pizza_name = pizza_name + c;
   }
   cout << pizza_name << endl;

}

My knowledge of C++ only goes back a single day (that's how long I've been doing C++, ouch), so don't blame me if I'm wrong, but can you typecast or use a pointer?

Well I said I can not type cast in about 3 or so other posts, gives me an error. And now that I have a string...... Game Maker gives me a stupid error. One problem after the other.

Also if I just return it as (float) b.to_ulong it gives me the acsii code for the letter. Why is it giving me the ascii code and not binary?

And I think an LPSTR is basically a char array, once you have a string, then you can store that into a char array:

Code:

char carray[100];
strcpy( carray, pizza_name.c_str() );

Or if your LPSTR already has memory allocated for it, then use strcpy() to copy to the LPSTR.

EDIT: added c_str()

>(float) b.to_ulong
You don't want float, you want char:
(char) b.to_ulong()
That will give you one char, which you could store straight to a char array, if you wish.

Allright I think all problems on the C++ side are fixed so the rest is up to me now.

Thanks alot!

Code:

#include <bitset>
#include <iostream>
#include <string>
#include <sstream>

using namespace std;


int main()
{
	string binary;
	stringstream ss;
	bitset<8> b('a');
	ss << b;
	binary = ss.str();
	cout << binary << endl;
	cin.get();
	return 0;
}

is this the kind of string you wanted, the string of 1's and 0's?