Thread: Char to Int

I'm just trying to make this simple little thing that will decode ASCII into readable characters. The only problem is, the code I've got so far voids everything after a space. IE '39 20', meaning 20 would be completely ignored...

I've tried a lot of stuff, but I can't think of anything that makes it work.

Code:

/*
    BUGS:
	Voids any ASCII after a space.
*/

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{ 
	char str[1024];
	int i;

	cout << "Enter some some ASCII:" << endl;
		cin.getline ( str, 1024 );

	i = atoi(str);
	cout << char(i);

	getch();
	return 0;
}

Oh alright. Thanks.

You need to convert each number entered separately. Use a loop and cin >> to read the numbers directly into the integer i, then cout each one the way you've done. That way you won't need atoi, and each number entered will be converted.

You mean, like a prompt everytime they want to add a new number?

If you just used cin >> then you might have to prompt for each one (or you could use a sentinal value to know when to stop - like 0 or -1).

Another option if you want them to be able to input multiple characters per line and convert each one is to use getline like you are doing, but then put the line into a stringstream and use the stringstream to extract the integers. This is easier to find the end of input because when the line is done the stream will return false.

One more option is to parse the string yourself and separate each number. This isn't a very good option IMO, but it works for some people who prefer C or are afraid to use C++.

I'll look into the stringstream way. Thanks for all your help.

> I have yet to find a language style that doesn't include string parsing...

I'm not sure you understood the context of the statement you quoted. I said "manually parsing", meaning writing your own code instead of using built-in or existing tools.

well i got an idea, cast the char to an int and youll get a number, and youll have to do something to that number to get the actuall number, figure it out yourself...