Comparing a 2d Array (newbie)

Hi all,
I am new to this world :)

I want to make a simple program that will compare the contents of a 2d array. Let's say array[a][b] have some integers in it. All I want to do is to make a simple program that will read the contents of array compare them and each time an integer in that array is repeated add one to that number.

Maybe this example might help:
Let's say i have c=array[a][b] and that I end up for a [2][2] array with
c=0
c=0
c=1
c=0
Now i want to be able to check this and say that in that array i have 3 zero's and one 1.

I have been trying to make somthing like this work but could not achieve it :(
All I got through was to read the contents of the array but not to compare it.

Any ideas of what i should do ?

Thanks

mm... couldn't get what ur meaning...
u want to check, in a 2d array, if u have a number twice???and if so, add 1 to that number??? or to a separate counter?????

I just want to count how many times a number of the array occurs. I do not want to add 1 to the number in the array. I just want to o........ the occurences of the contents of the array.

Thanks

This is what i have done so far but does not work i don't get values of counterarray[m] :(

#include <iostream.h>
main()
{
int i,m;
int j;
int array[4][2]={{1,2},{2,4},{3,6},{4,8}};
const int n=8;
int counterarray[n];



for(i=0;i<4;i++)
{
for(j=0;j<2;j++)
{
m=array[i][j];
counterarray[m]+=1;
cout<<counterarray[m]<<"\n";
}
}


}




Any ideas ???
thanks

Code:

---

#include <iostream.h>
int main(void)
{
int i,x,m = 0;
int j;
int array[4][2]={{1,2},{2,4},{3,6},{4,8}};
//const int n=8; ??
int counterarray[10];
for(x = 0;x<10;x++){counterarray[x] = 0;}


for(i=0;i<4;i++)
{
for(j=0;j<2;j++)
{
m=array[i][j];
counterarray[m]++;

}
}
for(x = 0;x<10;x++){
cout << "There were " << counterarray[x] << " instances of " << x << endl;
}

return 0;
}

---

That will count the instances of each number between 0 and 9...you can then play with it to get it to do exactly what you want

I THINK its becuase you never assign a value to counterarray.. You may only be incrimention how many spaces are in the array.

But im not entirely sure.

Thanks a lot guys :)

I think this might work afterall I'll get back to you shortly.

thanks

Yeap it did work. All that time i wasn't setting the counterarray to zero in the beggining of the program :)

Thanks a lot you guys :)

You know how it goes now that i solved that problem a new one came up :)
I'll keep you posted. Thanks a lot once again :)

hi again :)

I want to know how can I make my program to run with flags under windows?
example: prog [-h] [-run]
-h help flag
-run run prog flag

I know how I can do that to linux systems but don't know how to do it for windows based systems.

I'm using visual c++ to do my program under windows.

Any ideas?

Forget what i asked above i found the solution to that :)

New question :
How can find the summation of the contents of an array ?
I have a axb array and its contents are numbers ,how can i add them all up and get just a single result?

thanks

axb[NUM_ITEMS];
int total = 0;
int i = 0;
while (i <= NUM_ITEMS)
{
total += axb[i];
i++;
}
// NOT THE MOST EFFICIENT WAY, but works. Assuming the syntax is correct, sorry ive been up for 23 hours and counting.

How can I implement power and square root to my program? provided that i include math.h?

I did it like this
double pow(double x,double y);
double sqrt(double z);

but when compiling i got many errors some syntax about () and opother about double (i have int x,y,z) .

Any ideas?

Those functions are already defined in math.h, so all you have to do is call them.
result = pow(x, y);
result = sqrt(z);

-Prelude