function&arrays - please help...

I am trying to make a program using functions and arrays.....

It needs to recieve a character array buff of 6 characters. This would be entered by the user. Then the character array buff needs to be printed in the function...
for example
please enter information ==> 123456
output:
buff[0]==> 1
buff[1]==> 2
and so on

This is what i have so far.
#include<iostream.h> // need this!
#include<math.h> // need this!

int main() // need this!
{ // need this!

const char NUMBER = 6; // array declaration
int FUNPROT(int[NUMBER]); // function prototype

char code[NUMBER]; // array declaration
int FUNPROT(int[NUMBER]); // function prototype

char code[NUMBER]; // array declaration
int i;

// so that it repeats only 6 times.. if this wasnt here it would repeat forever
for(i=0; i<NUMBER; i++);
{
cout<<"Enter input here==>";

cin>>code[i];
}
int FUNPROT(int vals[NUMBER])
{
// print out character array in function
for(i=0; i<NUMBER; i++); // print out the number entered
}
}

I'm a little confused... any help would be appreciated.

thank you

marie10913@aol.com

PHP Code:

---


#include <iostream.h> // need this for Input/Output

// global variables and constants
const int NUMBER = 6;

// function prototypes
void FUNPROT( char vals[NUMBER] ); // function prototype 

int main()
{
     // variable declaration 
    char code[NUMBER];
    int i; 

    //code
    for( i = 0; i < NUMBER; i++ )
    { 
       cout << "Enter input #" << i + 1 << " here:" << flush; 
       cin >> code[i]; 
    }

    FUNPROT( code );

    return 0;
}

// function implementation
void FUNPROT( char vals[NUMBER] ) 
{
    // variable declaration 
    int i;

    // code
    for( i = 0 ; i < NUMBER ; i++ )
    {
        cout << "Input " << i + 1 << " was: " << vals[i] << endl;
    }
} 


---

You have mixed up your types and prototypes and had some things in there twice. Make sure you know what you need those parts for that said "//need this!".

yeah, prototypes area always over the main()
i guess ur having problems passing an array to the function, dont u????
well, to do so, u dont have to put the [x] to thearray. i mean:

function(hello[50], y); isnt correct. u go:

function(hello, y);


the reazon of been this way is that in the prototype:
void function(char [], int);
u define, that the first entrance will be an array....

oh,... an other thing.
when u make a define, u dont put

#define int NAME= 6

u go:

#define NAME 6

hope it worked....

the help i have recieved was great...

i just have one question about the suggestion...

cout << "Enter input #" << i + 1 << " here:" << flush;

on this line what does flush mean or do...

thank you

marie10913@aol.com

flush

You can leave it out. It just means that this line has to be printed right then. It must not be buffered. Just leave it out, you don't need it.

Just delete the "<< flush" part.

;)