bitwise question

This is a discussion on bitwise question within the C++ Programming forums, part of the General Programming Boards category; If I have the first byte of an int set to 00111011, where the last two ones are flags, how ...

  1. #1
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    bitwise question

    If I have the first byte of an int set to 00111011, where the last two ones are flags, how do I get the first 6 numbers and then convert them to a number so I can print it out. EX:

    I have 00111011 and I want to get the 001110 out of it, and change that to its own number, without getting/changing the last two ones. I hope this doesn't seem too complicated. Thanks!

  2. #2
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    If the other bytes of your integer are 0s, then all you need to do is this:

    int a = 0x0000003b;
    int b;
    b = a >> 2; //shift right 2 bits
    cout << hex << b << endl;


    If you need to mask the higher bytes, then do this:
    int a = 0xffffff3b;
    b = (a & 0xff) >> 2;
    cout << hex << b << endl;

    Or use all shifts:
    b = a << 24 >> 26; //shift left 24 bits, then right 26 bits

    This assumes your integer is 4 bytes. To find this out, print out the value of sizeof(int).

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