I found this while looking through the blowfish encryption algorithm, I am looking for techniques for my own and I dont quite understand this portion:

I know that the union type Word can be accessed as a WordByte, and i take it that its somehow organized from 4 bytes with 8 bits each? how do these numbers relate? sorry I blanked.Code:struct WordByte { unsigned int three:8; unsigned int two:8; unsigned int one:8; unsigned int zero:8; }; union Word { unsigned int word; WordByte byte; };