can any one tell why is output is bit stange

Code:

#include<iostream>

using namespace std;

bool testsame(int val1, int val2)
{
    if(val1==val2)
    return true;
    else
    false;
}


int main()
{
    if(testsame(12, 23))
    cout<<"Both values  are same"<<endl;
    else
    cout<<"Values are not same"<<endl;
    
    cin.get();
}

and my output is

Code:

Both values are same

but the output is wrong. i know the problem where it is. it in the function testsame

Code:

return true;
    else
    false;
}

when i put return in front of false everything seems tom work fine. i get correct answer. i dont understand why it is?? can any one tell me why this happens if i dont put return keyword keyword

thank you

s.s.harish

return false;

Since the function is supposed to return a boolean value, whatever you want to return needs to have "return" in front of it. So just like The Brain said, and as you already realized, you need the "return" keyword in front of "false" if you want to return the value as false if the two numbers aren't equal to each other.

If you don't put the "return" there, then "false;" is just a statement that does nothing. At that point your function returns without having a value to return. You probably got a warning about reaching the end of a non-void function without returning a value or something like that. When you don't specify a return value, the compiler could return anything it wants, normally whatever garbage is in the memory/register at the time. Since false is 0 and true is anything non-zero, chances are that a non-zero value is what is returned, and so the return value is equivalent to true. On another compiler or another machine the output might end up being correct. The point is that the behavior is undefined, and so you shouldn't rely on code like that working or not working, you should just fix the code as you did by adding the return.

thax david thats i what i wanted to know. i knew it was rongh, but i wanted to know the reason why.

thax very much

s.s.harish