Thread: small code question

Code:

#include <iostream.h>
int main ()
{
  int x;
  x = 5;
  int y; 
 
 cout << "enter choice here:  ";
  cin >> y;
  if (y == x)
   cout << "yes";
   else
  cout << "no";
  return 0;
}

well, a small question. when I run this (using bloodshed.net Dev-c++ compiler), after pressing enter after entering any number, letter etc, the window closes.

yes this is noobish, and yes ive looked around.

i THINK my if/else and cin tags are all right, but can someone just tell me how to work that (you should be able to tell what im trying to do. guess a number, if x, output "yes" if not output "no".

thanks.

this would solve this problem and others for me.

at the end, put cin.get(); , before the bracket and return 0 thing that is.

that's one of the things, well, the only thing i've tried. doesn't help. or at least not for me....

start your program from the command prompt.

Hrmm.. that works for me... strange.

oh, i just edited my last post saying i got it to work via cmd.

buy why does it work there...

skynet-systems....so you just inserted the code into a compiler, compiled, ran it and it worked? did you enter a number and get a response?

Originally Posted by nigy

oh, i just edited my last post saying i got it to work via cmd.

buy why does it work there...

Because you allready have a console provided by cmd.exe. When you double click the program and it exits it's console is closed.

Ok, yes, all goes well in command prompt, but when running it, will those codes let me see my final product? using

Code:

cin.get();

, the window stays open for a simple

Code:

cout << "__";

, but anything requiring user input, aka

Code:

 cin >>___;

, after entering something and pressing enter, the window finally closes, or a program that counts down starting with some number manually inputed, when it finally reaches 0, the window closes.

yes, im takign tooo long to say this....but the one on one of salem's links shows mea "C++ implementation using C++" looks a lot like just

Code:

cin.get();

.

ahhhhh, sorry, im rambling. will any of that code in the link help hte window open...for ever untill closed?

ok so...

Code:

cin.get();

is a function that gets a variable from the keyboard, so basically by putting it at the end of your file, just delays it untill it gets that input from the keyboard.
basically what people are saying is that you should have a input at the end before it closes so you can see whats going on.

if you want your program to keep doing it untill you want it to exit by entering a special variable (like exit, 0, -1...etc)

than your going to want to put it in a while loop.
for example.

Code:

#include <iostream>     //iostream.h is an old header file, better to use iostream
using namespace std;

int main ()
{
   int x;
   x = 5;
   int y; 
 
   while( x != -1 )
   {
      cout << "enter choice here (-1 to exit) :  ";
      cin >> y;
      if (y == x)
         cout << "yes";
      else
         cout << "no";
   }
   return 0;
}

Code:

#include <iostream>
  
  
using namespace std;

  int main (void)
{
     
  int x;
  x = 5;
  int y; 
  int z;
  
  
  
  while (x != y)
  {
  cout << "enter a number here: ";
  cin >> y;
  
  
  if (y == x)
  
  cout << "yes, oh boy, you got it.";
  
  else if (y > x)
  cout << "no, ur wrong. It's lower. type 0 and press enter to try again.";
  
  else
  cout << "no, ur wrong. It's higher, type 0 and press enter to try again.";
  cin >> y;
}


  return 0;
}

this is what i have, similar to what you said josh, and smurfs is right. I think.

My next step is to ad a random function to X so it's not always 5, but looking around ive not found a simple way to have it be between 1 and 100. YOu can give me the code if you really feel like it or not...your choice.

is there a way to do do

Code:

if (y == -10
exit

is there a function in c++ that closes the window after completing requirement of sorts?