Hi guys,

Ok this is more to do with laziness than anything else but I was wondering how would you create a program that cancels down fractions into its simplest form. I've managed to do it for positive integers but I have a problem when dealing withnegativeintegers.

Remember these rules:

Possible solutions include using theCode:+ / + = + + / - = - - / + = - - / - = + so: = -6 --- -10 = 3 --- 5absolutefunction, or perhaps converting the integer to a string and then checking to see if the first element in that array is equal to '-' or '+' and then doing the necessary arithmetic manipulations.

If you can see a quick easy solution, I would be most grateful.

Here's my code so far, note it only handles positive integers!

Code:#include <iostream> #include <stdlib.h> #include <math.h> using namespace std; int main() { int top_part; int bottom_part; int smallest; cout<<"Enter top part of fraction:"; cin>>top_part; cout<<"Enter bottom part of fraction:"; cin>>bottom_part; if (top_part>bottom_part) { smallest=bottom_part; } if (top_part<bottom_part) { smallest=top_part; } double it,its,newtop,newbot; for (int a=1; a<=smallest; a++) { it=top_part%a; its=bottom_part%a; if (it==0) { if (its==0) { newtop=top_part/a; newbot=bottom_part/a; } } } cout<<"When cancelled down..."<<endl; cout<<newtop<<"/"<<newbot; int stop; cin>>stop; return 0; }