Thread: new to Void functions and loops

I need to print a box out on the screen.
I am learning void functions (and have not learned about for yet)
I am able to print the top and bottom lines, but I just can not figure out how to get the 2 middle lines to print. I am giving this information in my instructions:
the interior dimensions are (numSigns-2) * (numSigns /2-2)
and the program promts for the number of $ for the top of the box. That number /2-2 lines are printed with $ on the sides;
Here is what i have so far:
void Print(int numSigns);


// FILL IN documentation.

int main ()
{
int number;

cout << "Enter the number of dollar signs for the top; "
<< "press return. " << endl;
cout << "Enter end-of-file characer to quit." << endl;
cin >> number;
while (cin)
{
/* FILL IN call to Print */

Print(number);
cout << endl;
Print(number);
cout << endl;

cout << "Enter the number of dollar signs for the top; "
<< "press return. " << endl;
cout << "Enter end-of-file characer to quit." << endl;
cin >> number;
}
return 0;
}

//*******************************************

void Print(int numSigns)
// FILL IN documentation.
{
/* FILL IN code to print numSigns $'s */

int count;
count = 0;

while (count <= numSigns)
{
cout << "$";
count++;
}
//********************************************

/* FILL IN code to print (numSigns / 2)-2 lines with */
/* $'s lining up under the left-most and right-most */
/* $ ones on the top line. */

/* FILL IN code to print numSigns $'s */

}

Please help....I have been at this all day!

Is this what you need?

Code:

void printBox(void){
    int n;
    cout << "How many lines? (1-40): ";
    cin >> n;
    for(int i = 0; i < n; i++){
        for(int j = 1; j <= 2*n; j++)
            cout << (i > 0 && i < n - 1 && j > 1 && j < 2 * n ? ' ' : '$');
        cout << endl;
    }
}

FOR is a loop, it just looks different than a while, these two loops are equivalent.

Code:

// a for loop
for(int i=0; i<10; i++){
    cout << i << endl;
}

// a while loop
int i = 0;
while(i<10){
    cout << i << endl;
    i++;
}

Here's the same program simplified a bit

Code:

void printBox(){
    int n;
    cout << "How many lines? (1-40): ";
    cin >> n;
    int i = 0;
    while(i < n){
        int j = 1;
        while(j <= 2*n){
            // && means AND. This if has 4 conditions to be met
            if(i > 0 && i < n - 1 && j > 1 && j < 2 * n){
                cout << ' ';
            }else{
                cout << '$';
            }
        }
        cout << endl;
    }
}