undeclared (first use this function)

Hello all. I just started trying to learn how to program and I have been studying the tutorials here and reading C++ Programming in easy steps by Mike McGrath. I have the first three lessons down pretty well, but I get in over my head about halfway through Functions. So I went back to Lesson 2: If Statements and tried to write my own little program for my out-of-town gf.

Code:

#include <iostream>

using namespace std;

int main ()
{ 
    int name;
    
    cout<<"Please give your full name. Don't forget your capitalization.: ";
    cin>> name;
    cin.ignore();
    if ( name == Jennifer ***** ******** ) {
         cout<<"Hello love.\n";
    }
    else {
         cout<<"Hey! What have you done with my girlfriend?!\n";
    }
    cin.get();
}

I get these errors:
`Jennifer' undeclared (first use this function)
(Each undeclared identifier is reported only once for each function it appears in.)

If I change this line

Code:

 if ( name == Jennifer ***** ******** ) {

To this

Code:

if ( name == "Jennifer ***** ********" ) {

I get this error
ISO C++ forbids comparison between pointer and integer

This is what I was using as a reference

Code:

#include <iostream>	

using namespace std;
		
int main()                            // Most important part of the program!
{
  int age;                            // Need a variable...
  
  cout<<"Please input your age: ";    // Asks for age
  cin>> age;                          // The input is put in age
  cin.ignore();                       // Throw away enter
  if ( age < 100 ) {                  // If the age is less than 100
     cout<<"You are pretty young!\n"; // Just to show you it works...
  }
  else if ( age == 100 ) {            // I use else just to show an example 
     cout<<"You are old\n";           // Just to show you it works...
  }
  else {
    cout<<"You are really old\n";     // Executed if no other statement is
  }

  cin.get();
}

I took out the else..if because in my case it is either right or wrong, and I really don't know what else to try. I know this is extremely basic but I am having trouble grasping any of it.

Thanks for any help.

First of all for an input of a character, name has to be declared as a char type instead of int, int is for numbers. second:

Code:

if ( name == Jennifer ***** ******** )

whats with the *? if you just want to see if its Jennifer,
cant you do this?

Code:

 if (name == 'Jennifer')

You need to store the users response in a data type that is appropriate to what you expect. In this case, you cannot store a person's name in an integer variable, integers store numbers and are not suited to storing a string of characters. What you are probably looking for is a string container.

Code:

#include <iostream>
#include <string>

using namespace std;

int main ()
{ 
    string name;
    
    cout<<"Please give your full name. Don't forget your capitalization.: ";
    getline(cin,name);
    cin.ignore();
    if ( name == "Jennifer ***** ********" ) {
         cout<<"Hello love.\n";
    }
    else {
         cout<<"Hey! What have you done with my girlfriend?!\n";
    }
    cin.get();
}

couldnt you use a switch also? sorry i am unfamiliar with strings, learning them in my next lesson :-P

Originally Posted by JoshR

whats with the *?

The * are so I don't post her full name on the internet.

So the getline (cin,name); takes the user's input (cin) and compares it to what I have specified, which is the string name;?

Thanks for the help

getline simply reads a line from the stream 'cin', and stores what it read in into the variable 'name' (in this case). The comparison is done inside the conditional 'if ( ... comparison-here ... )', which is demonstrated by hk_mp5kpdw.

A switch will only work for integral types: int, char, enum, etc.

Taken directly from lesson 9:

If you want the user to input his or her name, you must use a string.