Thread: Random Number Generator?

You need both ignore() (to eat the newline the user entered) and get() (to keep your console window from closing).

Code:

#include <iostream>

using namespace std;

int main ( int argc , char** argv ) 

{ 
    srand(time(0));
    int random_number = rand() % 10 + 1 ;
    cout << "Guess a number between 1 and 10\n";
    int guess;
    cin >> guess;
    if (guess==random_number)
    {
        cout << "Correct!";
    }
    else if (guess!=random_number)
    {
        cout << "Wrong!";
    }
    cin.ignore(80,'\n');
    cin.get();
}

>Ok, so now that works,
How can it work and not create an .exe? If:
"Guess a number between 1 and 10"
pops up, then there's an exe somewhere.

Originally Posted by DZeek

I tried cin.get(); but it still closes after you guess a number (cin >> guess; ).
Before the window closes, I can see it show "Correct" or "Wrong", but it doesn't ask for input again. It just closes.

ok , ( tell me if I'm wrong ) I think it gets affected by the other cin in your program : it kinda skips it. what you can do is put two cinget(); after eachother... ok its not the best code but I'm sure it works ( or cin.get(); cin.ignore(); )