Representing a Large Integer with an Array

This is a discussion on Representing a Large Integer with an Array within the C++ Programming forums, part of the General Programming Boards category; I'm a real beginner. I'm trying to create an array of integers to represent a very large number (three digits ...

  1. #1
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    Representing a Large Integer with an Array

    I'm a real beginner. I'm trying to create an array of integers to represent a very large number (three digits of the number per element of the array). I'll start out by reading two large numbers as strings from a file, and converting each of them to an integer array. Then I need to perform addition, subtraction, and multiplication on these two arrays, and store the results in a third array. Then, I'll convert the resulting integer array back into a string and output it.

    The sizes of the arrays and the segment of code used to add the numbers (below) were given to me by my professor. He also gave us the basic idea for converting to/from a string/integer array, but I'm quite sure I haven't executed it correctly. Here's what I've got so far, just for the addition operation:

    Code:
    void main()
    {
        int i, ca, length1, length2, length3, t;
        char s1[20], s2[20], s3[20];   //s1, s2 are read from file, s3 will be printed result
        int a[16], b[16], c[16];  //used in performing arithmetic operations
        FILE *ff;
        
        ff = fopen("a.txt", "r");
        
        fscanf(ff, "%s", s1);  //1st large number
        fscanf(ff, "%s", s2);  //2nd large number
        length1 = strlen(s1);
        length2 = strlen(s2);
    
    //CONVERTS LARGE NUMBER STRINGS TO INT ARRAYS
        for(i = 0; i < 16; i++){
            a[i] = (s1[length1 - (3 * i + 3)] - 48)*100 + (s1[length1 - (3 * i + 2)] - 48)*10 + (s1[length1 - (3 * i + 1)] - 48);
            b[i] = (s2[length2 - (3 * i + 3)] - 48)*100 + (s2[length2 - (3 * i + 2)] - 48)*10 + (s2[length2 - (3 * i + 1)] - 48);
        }
    
    //TO ADD THE TWO ARRAYS
        for(i = 0; i < 22; i++){   //adds
            c[1] = a[i] + b[i];
        }
        for(i = 0; i < 21; i++){  //rectifies carry-over from addition
            ca = c[i] / 10;
            c[i] = c[i] % 10;
            c[i + 1] = c[i + 1] + ca;
        }
    
    //CHANGE RESULTING INT ARRAY INTO A STRING
        for(i = 0; i < 16; i++){
            s3[i] = c[3 * i] % 10 + 48;
            c[3 * i] = c[3 * i] / 10;
        }
    
        length3 = strlen(s3);
    
    //REVERSES STRING
        for(i = 0; i < length3 / 2; i++){
            t = s3[i];
            s3[i] = s3[length3 - i - 1];
            s3[length3 - i - 1] = t;
        }
    
    //PRINTS RESULT FROM ADDITION    
        printf("The sum is %s \n", s3);
        
        fclose(ff);
    }
    Does this look remotely close at all?

  2. #2
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    First off, this should be moved to the C forum instead of the C++ forum.

    Oh, and welcome to the boards.

    Hmm....it seems like the code you're using to concatenate numbers is kinda inefficient-ish, eh? The way you're "converting" the strings into array elements seems that way, at least.
    Last edited by Krak; 03-02-2005 at 09:23 PM.

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    Thanks lol.

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